Question

我有以下表格：

class TestFormType extends AbstractType
{
    protected $testArgument;

    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        if (isset($options['testArgument'])) {
            $this->testArgument = $options['testArgument'];
        }

        $builder->add('textField', 'Symfony\Component\Form\Extension\Core\Type\TextType');
    }

    public function configureOptions(OptionsResolver $optionsResolver)
    {
        $optionsResolver->setRequired('testArgument');

        $optionsResolver->setDefaults(
            array(
                'data_class' => get_class($this->testArgument)
            )
        );
    }
}

我通过表单选项（Symfony 3修改）传递testArgument属性的值，但是什么时候获取属性的类名来设置'data_class'里面configureOptions方法，始终是null。基本上我需要依赖于configureOptions方法中的表单类型类属性。有人可以帮我在这里找到正确的方向吗？

Answer 1

我必须从表单工厂create方法本身传递$form = $this->factory->create( 'app\TestBundle\Form\Type\TestFormType', $this->testArgument, array( 'data_class' => get_class($this->testArgument) ) );方法中的依赖项：

class TestFormType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('textField', 'Symfony\Component\Form\Extension\Core\Type\TextType');
    }
}

因为它不会被表单类型中的默认设置设置，并且必须重构表单类型类，如下所示：

# function returning a decorator, takes arguments
def message(param1, param2):
    # this does the actual heavy lifting of decorating the class
    # this function takes a class and returns a class
    def wrapper(wrapped):

        # we inherit from the class we're wrapping (wrapped)
        # so that methods defined on this class are still present
        # in the decorated "output" class
        class WrappedClass(wrapped):
            def __init__(self):
                self.param1 = param1
                self.param2 = param2
                # call the parent initializer last in case it does initialization work
                super(WrappedClass, self).__init__()

            # the method we want to define
            def get_message(self):
                return "message %s %s" % (self.param1, self.param2)

        return WrappedClass
    return wrapper

@message("param1", "param2")
class Pizza(object):
    def __init__(self):
        pass

pizza_with_message = Pizza()

# prints "message param1 param2"
print pizza_with_message.get_message()

Answer 2

您应将* Type __constructor传递给

use App\Entity\Blog;  use Symfony\Component\Form\AbstractType;  use Symfony\Component\OptionsResolver\OptionsResolver;

class BlogType extends AbstractType {
    private $someDependency;

    public function __construct($someDependency)
    {
        $this->someDependency = $someDependency;
    }
    // ...

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults([
            'empty_data' => new Blog($this->someDependency),
        ]);
    } }

将参数传递给Symfony 3表单configureOptions

2 个答案: