Question

无法解析JSON数据。

无法转换类型＆＃39; __ NSArrayI＆＃39; （0x10f02fc08）到＆＃39; NSMutableArray＆＃39; （0x10f02fcd0）。

JSON数据here和此处的代码;

echo json_encode($resultArray);

这是我的试用代码;

func parseJSON() {
    var jsonResult: NSMutableArray = NSMutableArray()

    do{
        jsonResult = try JSONSerialization.jsonObject(with: self.data as Data, options:JSONSerialization.ReadingOptions.allowFragments) as! NSMutableArray
    } catch let error as NSError {
        print(error)
    }

    var jsonElement: NSDictionary = NSDictionary()
    let locations: NSMutableArray = NSMutableArray()

    for i in 1...jsonResult.count
    {
        jsonElement = jsonResult[i-1] as! NSDictionary

        let location = LocationModel()

        if let name = jsonElement["Name"] as? String,
            let address = jsonElement["Address"] as? String,
            let latitude = jsonElement["Latitude"] as? String,
            let longitude = jsonElement["Longitude"] as? String
        {
            location.name = name
            location.address = address
            location.latitude = latitude
            location.longitude = longitude

        }
        locations.add(location)
    }
    DispatchQueue.main.async(execute: { () -> Void in

        self.delegate.itemsDownloaded(items: locations)

    })
}

Answer 1

注意：它将修复THIS

而不是：

var jsonResult: NSMutableArray = NSMutableArray()

这样做：

var jsonResult: NSArray = NSArray()

而不是：

jsonResult = try JSONSerialization.jsonObject(with: self.data as Data, options:JSONSerialization.ReadingOptions.allowFragments) as! NSMutableArray

这样做：

jsonResult = try JSONSerialization.jsonObject(with: self.data as Data, options:JSONSerialization.ReadingOptions.allowFragments) as! NSArray

完整代码：

func parseJSON() {
    var jsonResult: NSArray = NSArray()
    do{
        jsonResult = try JSONSerialization.jsonObject(with: self.data as Data, options:JSONSerialization.ReadingOptions.allowFragments) as! NSArray
    } catch let error as NSError {
        print(error)
    }

    var jsonElement: NSDictionary = NSDictionary()
    let locations: NSMutableArray = NSMutableArray()

    for i in 1...jsonResult.count
    {
        jsonElement = jsonResult[i-1] as! NSDictionary

        let location = LocationModel()

        if let name = jsonElement["Name"] as? String,
            let address = jsonElement["Address"] as? String,
            let latitude = jsonElement["Latitude"] as? String,
            let longitude = jsonElement["Longitude"] as? String
        {

            location.name = name
            location.address = address
            location.latitude = latitude
            location.longitude = longitude

        }

        locations.add(location)

    }
    DispatchQueue.main.async(execute: { () -> Void in

        self.delegate.itemsDownloaded(items: locations)

    })
}

Answer 2

问题是JSONSerialization正在返回一个不可变的数组，而您只能将NSArray转换为NSMutableArray。相反，只需将其声明为NSArray：

func parseJSON() {
    var jsonResult: NSArray

    do {
        jsonResult = try JSONSerialization.jsonObject(with: data as Data) as! NSArray
    } catch let error as NSError {
        print(error)
        return
    }

    ...
}

或者，或者使用Swift的原生集合类型，而不是使用旧的NSArray和NSDictionary类型：

func parseJSON() {
    var jsonResult: [[String: Any]]  // this is an array of dictionaries

    do {
        jsonResult = try JSONSerialization.jsonObject(with: data as Data) as! [[String: Any]]
    } catch let error as NSError {
        print(error)
        return
    }

    for jsonElement in jsonResult {            
        if let name = jsonElement["Name"] as? String,
            let address = jsonElement["Address"] as? String,
            let latitude = jsonElement["Latitude"] as? String,
            let longitude = jsonElement["Longitude"] as? String
        {
            let location = LocationModel()
            location.name = name
            location.address = address
            location.latitude = latitude
            location.longitude = longitude
            locations.add(location) // or, if you defined `locations` to be a Swift array, `locations.append(location)`
        }
    }
    ...
}

（就我个人而言，我可能还会将data定义为Data而不是NSData，并将locations定义为[LocationModel]而不是NSMutableArray。）

如何在此SQL数据中使用NSArray和NSDictionary？

2 个答案: