Question

我正在使用类似于霍尔效应传感器的传感器来计算中断次数。经过一段随机时间后，通常在开启1-2小时后，它会重置并随机随机重置。

counter = 0;
sampletime = 0;
lastrisetime = tmr.now()
pin = 2

do
  gpio.mode(pin, gpio.INT)

  local function rising(level)
    -- to eliminate multiple counts during a short period (.5 second) difference is taken
        if ((tmr.now() - lastrisetime) > 500000) then
        lastrisetime = tmr.now();
    end
    -- when tmr.now() resets to zero this takes into account that particular count 
    if ((tmr.now() - lastrisetime) < 0) then
        lastrisetime = tmr.now();
    end
  end

  local function falling(level)
    if ((tmr.now() - lastrisetime) > 500000) then
        -- Only counted when the pin is on falling
        -- It is like a sine curve so either the peak or trough is counted 
            counter = counter + 1;
        print(counter)
        lastrisetime = tmr.now();
        sampletime = lastrisetime;
    end
    -- when tmr.now() resets to zero this takes into account that particular count 
    if ((tmr.now() - lastrisetime) < 0) then
        lastrisetime = tmr.now();
            counter = counter + 1;
        print(counter)
    end
  end

  gpio.trig(pin, "up", rising)
  gpio.trig(pin, "down", falling)
end

这是我在CoolTerm上遇到的错误，我每隔几个小时检查一次内存，你可以在那里看到结果。

NodeMCU 0.9.6 build 20150704  powered by Lua 5.1.4
> Connecting...
connected
print(node.heap())
22920
> print(node.heap())
22904
> print(node.heap())
22944
> print(node.heap())
22944
> 2. .print(node.heap())
22944
> print(node.heap())
22944
> ∆.)ç˛.ä‚¸ ã ¸@H7.àåË‘

NodeMCU 0.9.6 build 20150704  powered by Lua 5.1.4
> Connecting...
connected
 print(node.heap())
21216
> F.)ç˛.¶Ùå¶1.@H  .ÊÍ

NodeMCU 0.9.6 build 20150704  powered by Lua 5.1.4
> Connecting...
connected
H!à»©.ä‚D.ã ¸å¶H.åb‘

NodeMCU 0.9.6 build 20150704  powered by Lua 5.1.4
> Connecting...
connected
 print(node.heap())
22904
> print(node.heap())
21216
>

感谢您抽出宝贵时间阅读本文。感谢您的意见。

Answer 1

可能的看门狗定时器问题。

在您的中断服务程序中，您似乎在等待太多。

最好从那里删除定时操作，只需设置一个标志，在另一个循环中，检查标志状态并完成定时操作。

Answer 2

NodeMCU 0.9.6 build 20150704，由Lua 5.1.4提供支持

首先要使用最新版本的NodeMCU固件。 0.9.x很古老，包含很多错误，不再受支持。见https://github.com/nodemcu/nodemcu-firmware/#releases

lastrisetime = tmr.now（）

真正的问题是我相信tmr.now()会在2147秒翻身。我在I learned about this工作时proper debounce function。

-- inspired by https://github.com/hackhitchin/esp8266-co-uk/blob/master/tutorials/introduction-to-gpio-api.md
-- and http://www.esp8266.com/viewtopic.php?f=24&t=4833&start=5#p29127
local pin = 4    --> GPIO2

function debounce (func)
    local last = 0
    local delay = 50000 -- 50ms * 1000 as tmr.now() has μs resolution

    return function (...)
        local now = tmr.now()
        local delta = now - last
        if delta < 0 then delta = delta + 2147483647 end; -- proposed because of delta rolling over, https://github.com/hackhitchin/esp8266-co-uk/issues/2
        if delta < delay then return end;

        last = now
        return func(...)
    end
end

function onChange ()
    print('The pin value has changed to '..gpio.read(pin))
end

gpio.mode(pin, gpio.INT, gpio.PULLUP) -- see https://github.com/hackhitchin/esp8266-co-uk/pull/1
gpio.trig(pin, 'both', debounce(onChange))

是什么导致我的Nodemcu / ESP 8266重置？

2 个答案: