递归字符串解压缩

Question

我正在尝试解压缩看起来如下的字符串：

输入：4（ab）

输出：abababab

输入：11ab

输出：aaaaaaaaaaab

输入：2（3b3（ab））

产出：bbbabababbbbababab

以上示例均使用下面的递归方法正确显示，但在输入类似内容时会出现问题：

输入：4（ab）a

预期产量：ababababa

输入：2（3b3（ab））a

预期产量：bbbabababbbbabababa

我意识到问题出现在返回语句“返回重复”中。在当前状态下，递归继续，直到它到达输入字符串的末尾，即使在结束括号之后。基本上我不知道如果到达最后的括号如何让它破坏，然后如果还剩下什么就继续。在2（3b3（ab））a中它应该返回2 *（3b3（ab））+ a，现在它返回2 *（3b3（ab））a。非常感谢任何帮助，因为我无法理解它。

public static String decompress(String compressedText) throws Exception
{
   //BASE CASE 
    if(compressedText.length() == 1)
    {
        if(compressedText.charAt(0) == ')')
        {
            System.out.println("1: " + compressedText);
            return "";
        }
        else
        {
            System.out.println("2: " + compressedText);
            return compressedText;
        }

    }
    //END BASECASE


    if(compressedText.charAt(0) == '(')
    {
        System.out.println("3: " + compressedText);
        return decompress(compressedText.substring(1));        
    }


    //IF DOUBLE DIGIT
    if(Character.isDigit(compressedText.charAt(0)) == true && Character.isDigit(compressedText.charAt(1)) == true)
    {
        if(compressedText.charAt(3) != '(')
        {
            System.out.println("4: " + compressedText);
            int i = Integer.parseInt(compressedText.substring(0,2));
            String repeated = new String(new char[i]).replace("\0", compressedText.substring(2,3));  
            return repeated + decompress(compressedText.substring(3));
        }
        else
        {
            System.out.println("5: " + compressedText);
            int i = Integer.parseInt(compressedText.substring(0,2));
            String repeated = new String(new char[i]).replace("\0", decompress(compressedText.substring(2)));
            return repeated;
        }

    }
    //END DOUBLE DIGIT



    //IF SINGLE DIGIT
    if (Character.isDigit(compressedText.charAt(0)) == true)
    {
        if(compressedText.charAt(1) !='(')
        {
            System.out.println("6: " + compressedText);
            int i = Integer.parseInt(compressedText.substring(0,1));
            String repeated = new String(new char[i]).replace("\0", compressedText.substring(1,2));  
            return repeated + decompress(compressedText.substring(2)); 
        }
        else
        {
            System.out.println("7: " + compressedText);
            int i = Integer.parseInt(compressedText.substring(0,1));
            String repeated = new String(new char[i]).replace("\0", decompress(compressedText.substring(1)));
            return repeated;
        }

    }
    //END SINGLE DIGIT

    //IF RIGHT PARENTHESIS
    if (compressedText.charAt(0) == ')')
    {
        if (compressedText.charAt(1) != ')')
        {
            System.out.println("8: " + compressedText);
            return "";
        }
        else
        {
            System.out.println("9: " + compressedText);
            return  decompress(compressedText.substring(1));

        }

    }
    //END 

        System.out.println("10: " + compressedText);
        return compressedText.charAt(0)+decompress(compressedText.substring(1));

}