Question

我有一个存储过程，如下所示：

CREATE OR REPLACE FUNCTION public.sp_shared_asset_delete_by_id(
    "in_shared_asset_id" bigint,
    "in_client_uuid" uuid)
  RETURNS boolean AS
$BODY$
declare
"participant" cursor
begin
      "participant" is select * from get_all_participants("in_shared_asset_id");
      FOR row in "participant"
      LOOP
        --DELETE EACH PARTICIPANT
        sp_participant_delete_by_id(row.participant_id, row.created_by_client);
      END LOOP;
  return true;
end
$BODY$
  LANGUAGE plpgsql VOLATILE SECURITY DEFINER
  COST 100;

get_all_participants（“in_shared_asset_id”）返回一组“参与者”记录。

迭代get_all_participants调用返回的所有记录的正确方法是什么？目前，我得到一个plsql错误“接近”开始。

CREATE OR REPLACE FUNCTION public.get_all_partipants(in_shared_id bigint)
  RETURNS SETOF participant AS
$BODY$
begin
  return query select participant.participant_id,
                      participant.shared_asset_id,
                      participant.participant_role_type,
                      participant.user_external_ref_uuid,
                      participant.user_first_name ,
                      participant.user_last_name ,
                      participant.user_email_address,
                      shared_asset.asset_external_ref_uuid uuid,
                      shared_asset.owner_external_ref_uuid uuid,
                      participant.deleted_timestamp
               from participant
               join shared_asset
               on shared_asset.shared_asset_id = participant.shared_asset_id
               where shared_asset.shared_asset_id = "in_shared_id"
               and participant.deleted_timestamp is null;

end
$BODY$
  LANGUAGE plpgsql VOLATILE SECURITY DEFINER
  COST 100
  ROWS 1000;

Answer 1

你甚至不需要游标，但你的plsql语法看起来很奇怪。保持简单。

CREATE OR REPLACE FUNCTION public.sp_shared_asset_delete_by_id(
"in_shared_asset_id" bigint, "in_client_uuid" uuid) 
RETURNS boolean IS
DECLARE
  row participant%ROWTYPE;
BEGIN

  FOR row IN(SELECT * FROM get_all_participants("in_shared_asset_id"))
  LOOP
    --DELETE EACH PARTICIPANT
    sp_participant_delete_by_id(row.participant_id, row.created_by_client);
  END LOOP;
  RETURN TRUE;

END;
/

Answer 2

游标定义错误。它应该以{{1}}

结束

要使用光标，您需要OPEN它。

语法;错误（您在手册中找到那个）

您也没有声明保存游标返回的行的记录变量。您可以通过不使用显式游标变量并简单地loop over the query result

来简化它

"participant" is select *...

不相关，但是：CREATE OR REPLACE FUNCTION public.sp_shared_asset_delete_by_id( "in_shared_asset_id" bigint, "in_client_uuid" uuid) RETURNS boolean AS $BODY$ declare l_rec record; begin "participant" is ; FOR l_rec in select * from get_all_participants("in_shared_asset_id") LOOP --DELETE EACH PARTICIPANT perform sp_participant_delete_by_id(l_rec.participant_id, l_rec.created_by_client); END LOOP; return true; end $BODY$ LANGUAGE plpgsql VOLATILE SECURITY DEFINER COST 100;可以简化为普通的SQL函数。那里不需要PL / pgSQL。

PL / pgSQL迭代返回的类型

2 个答案: