Question

我创建了一个项目，它将检索提取的JSON数据并在UITableview中显示它。我不想通过下载所有内容来增加应用程序的负担。因此，只有当用户选择了一行时，它才会检索员工的详细信息。我正在使用页面视图控制器，以便用户可以通过滑动页面来浏览每个页面。 如何将dispatch_sync中发送的页面值发送到detailviewcontroller页面？

这是来自managePageviewController的代码

func viewDetailViewController(index: Int) -> DetailViewController? {
    if let storyboard = storyboard,
        page = storyboard.instantiateViewControllerWithIdentifier("DetailViewController") as? DetailViewController {        

                let currentEmployee = employeeStore.searchEmployee[index]

                getJson().testsearchJSON(currentEmployee.id, handler: {(employeeDetails) -> Void in
                    dispatch_sync(dispatch_get_main_queue(), {
                        page.employee = employeeDetails
                        page.employeeIndex = index
                        return page //fail here
                    })
                })
    }
    return nil
}

这是我的getJSON（）。testSearchJSON基金

func testsearchJSON(id:String, handler: (Employee) -> Void) {
    let requestURL: NSURL = NSURL(string: (favUrl + id))!
    let urlRequest: NSMutableURLRequest = NSMutableURLRequest(URL: requestURL)
    let session = NSURLSession.sharedSession()
    let task = session.dataTaskWithRequest(urlRequest) {
        (data, response, error) -> Void in

        let httpResponse = response as! NSHTTPURLResponse
        let statusCode = httpResponse.statusCode

        //retrieve data successfully
        if (statusCode == 200) {
            do {
                let json = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)
                if data!.length > 0 && error == nil {

                    guard let name = json["firstName"] as? String,
                    let title = json["title"] as? String,
                    let id = json["id"]!,
                    let manager = json["managerName"] as? String,
                    let oa = json["oa"] as? String,
                    let email = json["email"] as? String,
                    let department = json["department"] as? String,
                    let division = json["division"] as? String,
                    let company = json["company"] as? String
                    else {
                            return;
                    }
                    let newEmployee = Employee(id: String(id), name: name, title: title, manager: manager, oa: oa, email: email, department: department, division: division, company: company)

                    //test

                    handler(newEmployee)

                }
            } catch {
                print("Error with JSON: \(error)")
            }
        }
    }
    task.resume()
  }
}

这是我的DetailviewController页面

class DetailViewController: UIViewController, UITextFieldDelegate {

// MARK:- Propertise
@IBOutlet var employeePic: UIImageView! //employee picture
@IBOutlet var employeeName: UILabel! // name
@IBOutlet var employeeTitle: UILabel! //job title
@IBOutlet var dateCreated: UILabel!
@IBOutlet var managerName: UITextField!
@IBOutlet var oaName: UITextField!
@IBOutlet var emailField: UITextField!
@IBOutlet var departmentField: UITextField!
@IBOutlet var divisionField: UITextField!
@IBOutlet var companyField: UITextField!


var employee: Employee! {
    //add applicataion name
    didSet {
        navigationItem.title = employee.name
    }
}
//current employee index
var employeeIndex: Int!

let dateFormatter: NSDateFormatter = {
    let formatter = NSDateFormatter()
    formatter.dateStyle = .MediumStyle
    formatter.timeStyle = .NoStyle
    return formatter
}()

//MARK:- assign values
override func viewWillAppear(animated: Bool) {
    super.viewWillAppear(animated)

    employeeName.text = employee.name
    employeeTitle.text = "( " + employee.title + " )"
    emailField.text = employee.email
    managerName.text = employee.manager
    dateCreated.text = dateFormatter.stringFromDate(employee.dateCreated)
    oaName.text = employee.oa
    departmentField.text = employee.department
    divisionField.text = employee.division
    companyField.text = employee.company

    //retrieve image
    employeePic.thumbnails()
    employeePic.image = UIImage(named: "Default Image")

}

Answer 1

尝试喜欢这个

func viewDetailViewController(index: Int) -> DetailViewController? {
    if let storyboard = storyboard,
        page = storyboard.instantiateViewControllerWithIdentifier("DetailViewController") as? DetailViewController {        

                let currentEmployee = employeeStore.searchEmployee[index]

                getJson().testsearchJSON(currentEmployee.id, handler: {(employeeDetails) -> Void in
                        page.employee = employeeDetails
                        page.employeeIndex = index
                        return page //fail here
                })
    }
    return nil
}

func testsearchJSON(id:String, handler: (Employee) -> Void) {
    let requestURL: NSURL = NSURL(string: (favUrl + id))!
    let urlRequest: NSMutableURLRequest = NSMutableURLRequest(URL: requestURL)

    let semaphore = dispatch_semaphore_create(0);

    let session = NSURLSession.sharedSession()
    let task = session.dataTaskWithRequest(urlRequest) {
        (data, response, error) -> Void in

        let httpResponse = response as! NSHTTPURLResponse
        let statusCode = httpResponse.statusCode

        //retrieve data successfully
        if (statusCode == 200) {
            do {
                let json = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)
                if data!.length > 0 && error == nil {

                    guard let name = json["firstName"] as? String,
                    let title = json["title"] as? String,
                    let id = json["id"]!,
                    let manager = json["managerName"] as? String,
                    let oa = json["oa"] as? String,
                    let email = json["email"] as? String,
                    let department = json["department"] as? String,
                    let division = json["division"] as? String,
                    let company = json["company"] as? String
                    else {
                            dispatch_semaphore_signal(semaphore);
                            return;
                    }
                    let newEmployee = Employee(id: String(id), name: name, title: title, manager: manager, oa: oa, email: email, department: department, division: division, company: company)

                    //test

                    handler(newEmployee)
                    dispatch_semaphore_signal(semaphore);
                }
            } catch {
                dispatch_semaphore_signal(semaphore);
                print("Error with JSON: \(error)")
            }
        }
    }
    task.resume()
    dispatch_semaphore_wait(semaphore, DISPATCH_TIME_FOREVER)
  }
}

Answer 2

我认为在这种情况下，最好在DetailViewController中的viewDidLoad或viewWillAppear函数中编写数据。这样的事情：

在MainViewController中：

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
    viewDetailViewController(index : indexPath.row, employee: employeeStore.searchEmployee[indexPath.row])
}

func viewDetailViewController(index: Int, employee: Employee) {
    let detailController = storyboard.instantiateViewControllerWithIdentifier("DetailViewController") as? DetailViewController 
    detailController.currentEmployee = employee
    // present/push/etc detail controller
    present(detailViewController, animated: true, completion: nil)
}

在DetailViewController中：

var employee : Employee?
...

override func viewDidLoad() {
    super.viewDidLoad()
    if let employee = currentEmployee {
        getJson().testsearchJSON(employee.id, handler: {(employeeDetails) -> Void in
                dispatch_sync(dispatch_get_main_queue(), {
                    //reload UI for employeeDetails
             })
        })
    }
}

您也可以使用GCD等待块加载，例如GCD组。

如何将dispatch_sync（dispatch_get_main_queue（），{}中的值发送/返回到另一个页面

2 个答案: