Oracle喜欢模式匹配LIKE Con​​dition

Question

我需要使用类似条件的列，例如关注'UPDATE'

 UPDATE CUSTOMER_TRANSACTIONS ct
 SET PROCESSID = vQUARTER 
 where ct.CUSTOMERID = l_arrc1(i).CUSTOMERID 
 and ct.APPOINTOFCAID = l_arrc1(i).APPOINTOFCAID        
 and ct.INVOICEID like "'"||l_arrc1(i).INVOICEID||%||"'";

代替

UPDATE CUSTOMER_TRANSACTIONS ct
SET PROCESSID = '2015Q4'
where ct.CUSTOMERID = l_arrc1(i).CUSTOMERID 
and ct.APPOINTOFCAID = l_arrc1(i).APPOINTOFCAID        
and ct.INVOICEID like '0158741%';

INVOICEID和l_arrc1(i).INVOICEID是VARCHAR

怎么做？

Answer 1

您缺少适当的字符串分隔符，单引号：

UPDATE CUSTOMER_TRANSACTIONS ct
    SET PROCESSID = vQUARTER 
    WHERE ct.CUSTOMERID = l_arrc1(i).CUSTOMERID and
          ct.APPOINTOFCAID = l_arrc1(i).APPOINTOFCAID and      
          ct.INVOICEID LIKE l_arrc1(i).INVOICEID || '%' ;

SQL中字符串的相应分隔符是单引号而不是双引号。

Answer 2

假设INVOICEID为number列：

UPDATE customer_transactions ct
   SET processid = vQUARTER
 WHERE ct.customerid = l_arrc1(i).customerid
   AND ct.appointofcaid = l_arrc1(i).appointofcaid
   AND to_char(ct.invoiceid) LIKE to_char(l_arrc1(i).INVOICEID) || '%';

如果invoiceid不是number数据类型，则可以删除to_char