不调用C ++析构函数

时间:2016-12-13 11:50:48

标签: c++ destructor dynamic-allocation

我有三个课程:房间,门和世界

#include <set>;

using namespace std;

class Door; // Forward declaration

class Room {
public:
    Door* door1;
    Door* door2;

    Room(){}

    ~Room() {
        delete door1;
        door1 = 0;
        delete door2;
        door2 = 0;
    }
};

class Door {
public:
    Room* roomA;
    Room* roomB;

    Door(Room* roomA, Room* roomB) {
        this->roomA = roomA;
        this->roomB = roomB;
        linkRooms(); // This sets up the Door-Pointers in the Rooms
                     // so they know about the new door.
    }    

    ~Door() {
        // Returns the room-owned pointer pointing at this door
        getMyRoomPointer(roomA) = 0;
        getMyRoomPointer(roomB) = 0;
    }    

    Door * & getMyRoomPointer(Room * const & room) {
        if (room->door1 == this) return room->door1;
        else return room->door2;
    }

    void linkRooms() {
        roomA->door1 = this;
        roomB->door2 = this;
    }

};

class World {
public:
    std::set<Room*> rooms;

    World() {
        // Set up two rooms and link them using a door
        Room* newRoom = new Room();
        rooms.insert(newRoom);
        Room* anotherNewRoom = new Room();
        rooms.insert(anotherNewRoom);

        new Door(newRoom, anotherNewRoom);
    }
    ~World() {
        // Iterate over the rooms and call delete on all of them
        for (std::set<Room*>::iterator it = rooms.begin(); it != rooms.end(); ++it) {
            delete *it;
        }
    }
};

int main() {

    World world;

    return 0;
}

当运行main时,构造函数只用两个房间和一扇门作为它们之间的链接填充世界。主要回归后,世界应该被删除,所有的房间和门也应该被照顾。

问题是,我的门析构函数从未被调用过。因此房间内的门指针不设置为空,当“在另一侧”的房间试图删除同一扇门时,我收到错误。

当我刚刚创建一个Door实例,而不是之后删除它时,我没有遇到任何问题:

int main(){

    Room oneRoom;
    Room anotherRoom;

    Door* door = new Door(&oneRoom, &anotherRoom);
    delete door; // works just fine

    return 0;
}

问题:为什么没有调用Door构造函数?是否允许在第一个示例中设置Door?

我知道,我正在双重删除我房间的门指针,而且我可以(而且应该)使用SmartPointers。现在我只是想知道为什么我要面对这种行为。毕竟,我还是C ++的新手。

我现在设置了一个可运行的示例,它会重现错误。

3 个答案:

答案 0 :(得分:3)

您在定义delete之前致电Door。因此,程序的行为是未定义的,并且不能保证析构函数被调用。

标准(草稿)[expr.delete]的引用:

  
      
  1. 如果要删除的对象在删除时具有不完整的类类型,并且完整的类具有非平凡的析构函数或释放函数,则行为未定义。
  2.   

解决方案:如果类型的析构函数是非平凡的(即用户定义的,例如~Door,那么在类型完成之前永远不要删除这样的对象)。在这种情况下,请在调用delete的函数之前定义Door

作为一般规则,除非类类型完整,否则永远不能调用成员函数。不幸的是,在析构函数的情况下,编译器可能无法始终捕获错误。 PS。 g ++会警告你的程序:warning: possible problem detected in invocation of delete operator: [-Wdelete-incomplete]

答案 1 :(得分:2)

您应该注意编译器警告消息:

g++ -std=c++17 -fPIC -g -Wall -Wextra -Wwrite-strings -Wno-parentheses -Wpedantic -Warray-bounds -Weffc++      41120443.cpp    -o 41120443
41120443.cpp:1:15: warning: extra tokens at end of #include directive
 #include <set>;
               ^
41120443.cpp:7:7: warning: ‘class Room’ has pointer data members [-Weffc++]
 class Room {
       ^~~~
41120443.cpp:7:7: warning:   but does not override ‘Room(const Room&)’ [-Weffc++]
41120443.cpp:7:7: warning:   or ‘operator=(const Room&)’ [-Weffc++]
41120443.cpp: In constructor ‘Room::Room()’:
41120443.cpp:12:5: warning: ‘Room::door1’ should be initialized in the member initialization list [-Weffc++]
     Room(){}
     ^~~~
41120443.cpp:12:5: warning: ‘Room::door2’ should be initialized in the member initialization list [-Weffc++]
41120443.cpp: In destructor ‘Room::~Room()’:
41120443.cpp:15:16: warning: possible problem detected in invocation of delete operator: [-Wdelete-incomplete]
         delete door1;
                ^~~~~
41120443.cpp:15:16: warning: invalid use of incomplete type ‘class Door’
41120443.cpp:5:7: note: forward declaration of ‘class Door’
 class Door; // Forward declaration
       ^~~~
41120443.cpp:15:16: note: neither the destructor nor the class-specific operator delete will be called, even if they are declared when the class is defined
         delete door1;
                ^~~~~
41120443.cpp:17:16: warning: possible problem detected in invocation of delete operator: [-Wdelete-incomplete]
         delete door2;
                ^~~~~
41120443.cpp:17:16: warning: invalid use of incomplete type ‘class Door’
41120443.cpp:5:7: note: forward declaration of ‘class Door’
 class Door; // Forward declaration
       ^~~~
41120443.cpp:17:16: note: neither the destructor nor the class-specific operator delete will be called, even if they are declared when the class is defined
         delete door2;
                ^~~~~
41120443.cpp: At global scope:
41120443.cpp:22:7: warning: ‘class Door’ has pointer data members [-Weffc++]
 class Door {
       ^~~~
41120443.cpp:22:7: warning:   but does not override ‘Door(const Door&)’ [-Weffc++]
41120443.cpp:22:7: warning:   or ‘operator=(const Door&)’ [-Weffc++]
41120443.cpp: In constructor ‘Door::Door(Room*, Room*)’:
41120443.cpp:27:5: warning: ‘Door::roomA’ should be initialized in the member initialization list [-Weffc++]
     Door(Room* roomA, Room* roomB) {
     ^~~~
41120443.cpp:27:5: warning: ‘Door::roomB’ should be initialized in the member initialization list [-Weffc++]
41120443.cpp: In constructor ‘World::World()’:
41120443.cpp:56:5: warning: ‘World::rooms’ should be initialized in the member initialization list [-Weffc++]
     World() {
     ^~~~~

和Valgrind输出:

valgrind  ./41120443 
==2864== Memcheck, a memory error detector
==2864== Copyright (C) 2002-2015, and GNU GPL'd, by Julian Seward et al.
==2864== Using Valgrind-3.12.0.SVN and LibVEX; rerun with -h for copyright info
==2864== Command: ./41120443
==2864== 
==2864== Conditional jump or move depends on uninitialised value(s)
==2864==    at 0x4C2C291: operator delete(void*) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==2864==    by 0x108BC3: Room::~Room() (41120443.cpp:17)
==2864==    by 0x108D67: World::~World() (41120443.cpp:68)
==2864==    by 0x108B65: main (41120443.cpp:75)
==2864== 
==2864== Conditional jump or move depends on uninitialised value(s)
==2864==    at 0x4C2C291: operator delete(void*) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==2864==    by 0x108BA8: Room::~Room() (41120443.cpp:15)
==2864==    by 0x108D67: World::~World() (41120443.cpp:68)
==2864==    by 0x108B65: main (41120443.cpp:75)
==2864== 
==2864== Invalid free() / delete / delete[] / realloc()
==2864==    at 0x4C2C2DB: operator delete(void*) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==2864==    by 0x108BC3: Room::~Room() (41120443.cpp:17)
==2864==    by 0x108D67: World::~World() (41120443.cpp:68)
==2864==    by 0x108B65: main (41120443.cpp:75)
==2864==  Address 0x5a82e00 is 0 bytes inside a block of size 16 free'd
==2864==    at 0x4C2C2DB: operator delete(void*) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==2864==    by 0x108BA8: Room::~Room() (41120443.cpp:15)
==2864==    by 0x108D67: World::~World() (41120443.cpp:68)
==2864==    by 0x108B65: main (41120443.cpp:75)
==2864==  Block was alloc'd at
==2864==    at 0x4C2B21F: operator new(unsigned long) (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==2864==    by 0x108CCE: World::World() (41120443.cpp:63)
==2864==    by 0x108B54: main (41120443.cpp:75)

通过明智地使用智能指针,您可以让自己的生活更轻松:

#include <memory>
#include <set>

class Door; // Forward declaration

struct Room {
    std::shared_ptr<Door> door1 = {};
    std::shared_ptr<Door> door2 = {};

    ~Room();
};

struct Door {
    const std::weak_ptr<Room> roomA;
    const std::weak_ptr<Room> roomB;

    Door(std::shared_ptr<Room> roomA, std::shared_ptr<Room> roomB)
        : roomA(roomA),
          roomB(roomB)
    {
        roomA->door1 = roomB->door1 = std::shared_ptr<Door>{this};
    }

    ~Door() = default;
};

// Now that Door is complete, we can define ~Room
Room::~Room() = default;

struct World {
    std::set<std::shared_ptr<Room>> rooms = {};

    World() {
        // Set up two rooms and link them using a door
        auto newRoom = std::make_shared<Room>();
        rooms.insert(newRoom);
        auto anotherNewRoom = std::make_shared<Room>();
        rooms.insert(anotherNewRoom);

        new Door(newRoom, anotherNewRoom);
    }

    ~World() = default;
};

int main() {

    World world;

    return 0;
}

这构建并运行得很干净:

g++ -std=c++17 -fPIC -g -Wall -Wextra -Wwrite-strings -Wno-parentheses -Wpedantic -Warray-bounds -Weffc++      41120443.cpp    -o 41120443
valgrind  ./41120443 
==3254== Memcheck, a memory error detector
==3254== Copyright (C) 2002-2015, and GNU GPL'd, by Julian Seward et al.
==3254== Using Valgrind-3.12.0.SVN and LibVEX; rerun with -h for copyright info
==3254== Command: ./41120443
==3254== 
==3254== 
==3254== HEAP SUMMARY:
==3254==     in use at exit: 0 bytes in 0 blocks
==3254==   total heap usage: 7 allocs, 7 frees, 72,952 bytes allocated
==3254== 
==3254== All heap blocks were freed -- no leaks are possible
==3254== 
==3254== For counts of detected and suppressed errors, rerun with: -v
==3254== ERROR SUMMARY: 0 errors from 0 contexts (suppressed: 0 from 0)

答案 2 :(得分:0)

你永远不会删除门

new Door(newRoom, anotherNewRoom);

您应该在世界中添加Door *door

public:
  Door *door;

...

  door = new Door(newRoom, anotherNewRoom);

并在world的析构函数中调用delete:

delete door;

请注意,您的代码有很多未定义的行为。

std::set<Room *> rooms;

std::set是一个关联容器,包含一组有序的Key类型的唯一对象。

你应该使用list:

std::list<Room *> rooms;
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