Question

这可能非常简单，我可能会在此之后将自己踢出屁股，但是我有以下代码，它会显示表中数据的html或json并返回它。

<?php
session_start();
$base = dirname(dirname(__FILE__));
include($base."/include/db.php");

global $conn;
$trees = [];
$treeBoxes = [];
if(isset($_SESSION['clientId'])) {
    $clientId = $_SESSION['clientId'];
    $query = $conn->prepare("SELECT * FROM ct_trees WHERE client_id=?");
    $query->bind_param('i', $clientId);
    $query->execute();
    $result = $query->get_result();
    if($result->num_rows > 0) {
        while($row = $result->fetch_assoc()) {
            $tree_id = $row['id'];
            $tree_name = $row['name'];
            $query = $conn->prepare("SELECT id FROM ct_connections WHERE tree_id=?");
            $query->bind_param('i', $tree_id);
            $query->execute();
            $result2 = $query->get_result();
            $connections = $result2->num_rows;
            array_push($treeBoxes, '<span class="checkbox abc-checkbox abc-checkbox-success">',
            '<input id="tree'.$tree_id.'" type="checkbox" rel="'.$tree_id.'">',
            '<label for="tree'.$tree_id.'">'.$tree_name.'</label>',
            '</span>');
            array_push($trees, ["id" => $tree_id, "name" => $tree_name, "connections" => $connections]);
            if(isset($_GET['json'])) {
                echo json_encode($trees);
            } else {
                echo join("", $treeBoxes);
            }
        }
    }
}
?>

现在让我们说，我们想要json结果，我得到以下字符串：

[{"id":1,"name":"My Tree","connections":4360}][{"id":1,"name":"My Tree","connections":4360},{"id":4,"name":"Another Tree","connections":0}]

现在由于某种原因，它在一个数组中给出了第一个结果，然后是相同的结果，但是在其他行中，在一个单独的数组中。

Answer 1

修正了它，我知道这很愚蠢：

fa-fw

为什么这段代码会给我重复的结果？

1 个答案: