MySQL错误“ORDER BY子句的表达式#1不在GROUP BY子句中”

时间:2016-12-19 12:31:32

标签: php mysql mysql-error-1055

我正在尝试从表中获取记录总数并使用以下MySQL查询:

SELECT COUNT(*) AS cnt FROM `info` WHERE 1 GROUP BY FROM_UNIXTIME(signup_date, '%Y-%m-%d') ORDER BY signup_date DESC

但是导致以下错误:

  

SQL错误(1055):ORDER BY子句的表达式#1不在GROUP BY子句中,并且包含非聚合列'rentown.info.signup_date'   它在功能上不依赖于GROUP BY子句中的列;   这与sql_mode = only_full_group_by不兼容。[SELECT COUNT()   AS cnt FROM info WHERE 1 GROUP BY FROM_UNIXTIME(signup_date,   '%Y-%m-%d')ORDER BY signup_date DESC]

这是我的表格格式:

+ Options
    id  email   signup_date     ip  city_name   firstname   address     state   lastname    city    zipcode     phonenumber     current_url     creditscore
    4   kfct@yahoo.com  1388525440  108.200.78.136  Philadelphia, PA    Kathy   1915 Apex Ave #1/4  California  Yeung   Los Angeles     90039   310 890 3338    NULL    NULL
    10  mlh@gmail.com   1388884727  98.199.141.66   Dickinson, TX   Mackenzie   102 strand  Texas   Helms   Galveston   77550   409 599 8024    NULL    NULL
    11  mjma@yahoo.com  1388889053  99.190.210.155  Grand Prairie, TX   samathiis   1701 towne crossing blvd #731   Texas   ashley  mansfield   76063   817 210     NULL    NULL

2 个答案:

答案 0 :(得分:3)

错误消息非常明显。您只能按GROUP BY子句中出现的列或聚合排序。要快速修复,只需按分组时使用的相同术语排序。

SELECT COUNT(*) AS cnt
FROM `info`
GROUP BY FROM_UNIXTIME(signup_date, '%Y-%m-%d')
ORDER BY FROM_UNIXTIME(signup_date, '%Y-%m-%d') DESC

答案 1 :(得分:0)

对于总记录数,这应该足够了:

SELECT COUNT (*) AS cnt
FROM 'info'
ORDER BY signup_date DESC