我必须做以下练习。有人可以解释为什么示例中的3位未对齐？
/*
* A data stream contains a binary stream of data in little endian byte format.
*
* The binary data can be mis-aligned to byte boundaries.
* In order to indicate alignment to the consumer, a periodic alignment
* synchronisation sequence is output.
* The alignment sequence is defined as 4 bytes of 0x00 followed by a byte of 0x80.
*
* For example, the following stream is mis-aligned by 3 bits and has an alignment sequence followed by
* the byte values 0x01,0x02,0x03
*
* 0x65, 0x50, 0x00, 0x00, 0x00, 0x00, 0x04, 0x00, 0x08, 0x10, 0x18
*
* The sequence ends when there's not enough bits left to fill a byte
*
*/
此外，这是必须实现的界面
interface RawDataStream{
/*
* Reads raw data from a stream
*
* @param buffer to store read bytes in
* @param num_bytes number of bytes to read from the stream into the buffer
*
* @return number of bytes read from stream into buffer
* -1 no data in stream
* -2 End of stream
*/
int readBytes(char[] buffer, int num_bytes);
}
验证校准序列的最佳方法是什么？