Question

我正在尝试将ASCII字符串来回转换为二进制表示，如下所示。

s=chr(0)*15 + chr(0x01)
bst = bin(int(binascii.hexlify(s), 16))
n = int(bst, 2)
binascii.unhexlify('%x' % n)

但是，我在最后得到以下错误，这对我来说没什么意义。

1 binascii.unhexlify（'％x'％n）

TypeError：奇数长度字符串

问题是什么？如何解决？

Answer 1

使用python控制台：

>>> help(binascii.unhexlify)

unhexlify(...)
    a2b_hex(hexstr) -> s; Binary data of hexadecimal representation.

    hexstr must contain an even number of hex digits (upper or lower case).
    This function is also available as "unhexlify()"

所以错误是一致的。你需要做的是用'0'填充以得到偶数：

>>> binascii.unhexlify('0%x' % n)
'\x01'

Answer 2

                n = int(wer, 2)

                qqwslenf=len(wer)
                qqwslenf=(qqwslenf/8)*2
                qqwslenf=str(qqwslenf)
                qqwslenf="%0"+qqwslenf+"x"


                jlz=binascii.unhexlify(qqwslenf % n)
                #we convert from binary to ASCII exactly size of need by half bytes.

binascii.unhexlify的奇数字符串错误

2 个答案: