Question

我有两个日期： 2011-07-05 和 2013-10-05

如何获得格式的持续时间： 2 years 3 months 。什么是最好的方法？我可以为此创建任何扩展方法或新类吗？请指教？任何帮助将不胜感激

到目前为止我已经完成了：

 public static string GetDuration(DateTime date1, DateTime date2) {
    int oldMonth = date2.Month;
    while (oldMonth == date2.Month) {
        date1 = date1.AddDays(-1);
        date2 = date2.AddDays(-1);
    }

    int years = 0, months = 0;

    // getting number of years
    while (date2.CompareTo(date1) >= 0) {
        years++;
        date2 = date2.AddYears(-1);
    }
    date2 = date2.AddYears(1);
    years--;

    // getting number of months and days
    oldMonth = date2.Month;
    while (date2.CompareTo(date1) >= 0) {
        date2 = date2.AddDays(-1);
        if ((date2.CompareTo(date1) >= 0) && (oldMonth != date2.Month)) {
            months++;
            oldMonth = date2.Month;
        }
    }

    return 
        "Difference: " +
        years.ToString() + " years" +
        ", " + months.ToString() + " months";
}

Answer 1

public static string GetDuration(DateTime date1, DateTime date2) 
{
    TimeSpan difference = date2 - date1;
    DateTime result = DateTime.MinValue.AddDays(difference.TotalDays);

    int years = result.Year - 1;
    int months = result.Month - 1;
    int days = result.Day - 1;

    return $"{years} years {months} months";
}

Answer 2

public static string GetDuration(DateTime date1, DateTime date2) 
{       
    var period = date2.AddDays(1) - date1;
    var date = new DateTime(period.Ticks);
    var totalYears = date.Year - 1;
    var totalMonths = ((date.Year - 1) * 12) + date.Month - 1;
    var extraMonths = totalMonths - (totalYears * 12);

    return string.Format("{0} years {1} months", totalYears, extraMonths);
}

您可以查看实际操作here。

Answer 3

没有考虑实际日期，这是一个快速的解决方案

int year, month;

if(date2.Month >= date1.Month)
{
  years = date2.Year - date1.Year;
  months = date2.Month - date1.Month;
}
else
{
  years = date2.Year - date1.Year - 1;
  months= date2.Month + 12 - date1.Month;
}

获得数年和数月的持续时间

3 个答案: