我想知道为什么我无法使用
打印record[i][1]
puts (record[i][1]);
如果我这样做：
cout<< record[i][1];
然后只出现字符串的第一个字母，而不是其余字母。
这是针对学校项目的。
我在Turbo C ++（TC4）上编码。
#include< fstream.h>
#include< strstream.h>
#include< conio.h>
#include< dos.h>
#include< graphics.h>
#include< string.h>
#include< stdio.h>
#include< stdlib.h>
#include< string.h>
#include< ctype.h>
#include< iomanip.h>
#include< iostream.h>
char record[500][5]; //array to store 500 entries each consisting of
//name,cell no, agesex, crime and sentenced.
int cricode=1;
char name[35];
char criminalno[10];
char agesex[5];
char sentenced[3];
char crime[20];
char passwordU[30];
int checkpass(char[]);
void menu(int);
void advmenu(int);
void inputdata();
void report(int) ;
void searchrecN(char [][5], int);
void searchrecC(char [][5], int);
void selectcrime(char []);
void changepass();
void displaydata(int);
void main()
{
clrscr();
ifstream fp;
fp.open("criminal.txt");
do
{char a;
fp.getline(&record[cricode][1],30,'!') ; //name
fp.getline(&record[cricode][2],10,'@'); //cellno
fp.getline(&record[cricode][3],7,'%'); //agesex
fp.getline(&record[cricode][4],20,'^'); //crime
fp.getline(&record[cricode][5],3,'\n'); //sentenced
cricode++ ;
}while (fp.eof() == 0);
cricode--; //final value of cricode
fp.close();
menu(cricode);
getch();
}
void menu(int code)
{
fstream fp;
int hell;
clrscr();
cout<<"\n\n";
cout<<"______________________________________\n";
cout<<" L O C A L M E N U \n";
cout<<"______________________________________\n";
cout<<"\n\n";
cout<<"\t\t\t"<<"\n\n[1] Create a Record.";
cout<<"\t\t\t"<<"\n\n[2] Search for a record.";
cout<<"\t\t\t"<<"\n\n[3] Advance Options.";
cout<<"\t\t\t"<<"\n\n[4] Display all entries.";
cout<<"\t\t\t"<<"\n\n[5] Exit \n :";
cin>>hell;
switch(hell)
{
case 1: clrscr();
inputdata();
system("pause");
menu(code);
break;
case 2: clrscr();
char na[30];
int ch;
clrscr();
cout<<"\t\t\t"<<"\nSearch by -> ";
cout<<"\t\t\t\t"<<"\n[1] Name : ";
cout<<"\t\t\t\t"<<"\n[2] Cell No. : ";
cin>>ch;
switch(ch)
{
case 1:
cout<<"\n Please Enter Name : ";
//gets(na);
searchrecN(record,code);
break;
case 2:
cout<<"\n Please Enter Cell No. : ";
//gets(na);
searchrecC(record,code);
break;
default : cout<<"invalid";
}
menu(code);
break;
case 4: clrscr();
for(int i=0;i<code;i++)
{
cout<<"\nName \t Cellno \t age/sex \t crime \t sentenced \n";
cout<<record[i][1]; //only one character is displayed of the
// entire word.
// if i do
//puts(record[i][1]); // Error: cannot convert 'int' to 'const char *'
}
cout<<"\n";
system("pause");
menu(code);
break;
case 5: //clrscr();
//intro();
break;
default:
cout<<"\a";
}
}
int i;
void report(int cc)
{
cout <<record[cc][1]<<"\t"
<<record[cc][2]<<"\t"
<<record[cc][3]<<"\t"
<<record[cc][4]<<"\t"
<<record[cc][5]<<"\n";
}
void inputdata()
{
char ch;
char recname[30],reccell[10],recagex[7],recrime[20],recsent[3];
ofstream fp;
fp.open("criminal.txt", ios::app);
do
{
cout<<"\n[.] Name : ";
gets(recname);
cout<<"\n[.] Criminal Number : ";
gets(reccell);
cout<<"\n[.] Age/Sex {eg: 21/M} : ";
gets(recagex);
cout<<"\n[.] Select Crime : ";
selectcrime(recrime);
cout<<"\n[.] Sentenced For : ";
gets(recsent);
fp <<recname
<<"!"<<reccell
<<"@"<<recagex
<<"%"<<recrime
<<"^"<<recsent
<<"\n";
cout<<"Do you Want to Continue(Y/N): ";
cin>>ch;
}while((ch=='y')||(ch=='Y'));
system("pause");
}
void searchrecN(char record[][5], int cricode)
{
int cnt;
char search[30];
cout<<"Enter Cellno.: ";
gets(search);
for(i=0;i<cricode;i++)
{
if (strcmpi(search,&record[i][1])==0)
{
clrscr();
cout<<"\nRecord Found.";
cout<<"\nLoading Info......";
system("pause");
report(i);
cnt=1;
break;
}
}
if(cnt==0)
{
clrscr();
cout<<"\n ***Record does not exist*** ";
cout<<"\n ***Redirecting***\n";
system("pause");
}
}
void searchrecC(char record[][5], int cricode)
{
int cnt;
char search[10];
cout<<"Enter Cellno.: ";
gets(search);
for(i=0;i<cricode;i++)
{
if (strcmpi(search,&record[i][2])==0)
{
clrscr();
cout<<"\nRecord Found.";
cout<<"\nLoading Info......";
system("pause");
report(i);
cnt=1;
break;
}
}
if(cnt==0)
{
clrscr();
cout<<"\n ***Record does not exist*** ";
cout<<"\n ***Redirecting***\n";
system("pause");
}
}
void displaydata(int c)
{
clrscr();
fstream fp;
for(i=0;i<c;i++)
{
cout<<"Name\tCellno\tage/sex\tcrime\tsentenced";
cout <<record[i][1]<<"\t"<<record[i][2]<<"\t"
<<record[i][3]<<"\t"<<record[i][4]<<"\t"
<<record[i][5]<<"\n";
}
/* cout<<setw(100)<<"\n[.] Criminal No. : ";
puts(record[i][2]);
cout<<setw(100)<<"\n[.] Age/Sex : ";
puts(record[i][3]);
cout<<setw(100)<<"\n[.] Alleged for : : ";
// puts(obj[i].category);
cout<<setw(100)<<"\n[.] Crime : ";
puts(record[i][4]);
// cout<<setw(100)<<"\n[.] Expenses per month : ";
puts(record[i][4]);
/* cout<<setw(100)<<"\n[.] Expenses per Month : ";
cout<<exp;
cout<<setw(100)<<"\n[.] Sentenced for : ";
puts(record[i][5]); */
}
答案 0 :(得分：1)
您的record数组是一个包含500行 5个单个字符的数组，而不是5个字符串。
我建议您使用结构建模数据：
struct Record
{
char name[35];
char criminalno[10];
char agesex[5];
char sentenced[3];
char crime[20];
char passwordU[30];
};
您的数据库可以是500条记录：
Record database[500];
仅供参考，使用std::string和std::vector的更安全且不太麻烦的技术。
答案 1 :(得分：0)
简短回答是record[i][1]是一个char，而不是字符串。
答案越长，你为什么使用Turbo C ++ 4 ...... ???如果可以，请使用其中一个现代编译器 - MSVC或Clang或G ++或MinGW，甚至是melpon.org/wandbox等在线编译器。
完整的答案：如果您不能使用std::string而不是char[]，请使用C编程语言查找解决方案。您需要逐步浏览char[]中的每个元素并单独输出。像这样：
for(int i = 0; i < MAX_LENGTH && myCharArray[i] != '\0'; i++) {
std::cout << myCharArray[i];
}