Question

我是春天和jpa的新手。我搜索了类似的主题，仍然无法解决我的问题。我试图在我的测试文件中自动装配我的EmployeeRepository（Imp），但它总是返回null ...所有代码都在同一个包中。非常感谢你的时间。

另一个问题是我应该使用哪一个（我曾试过两个都没有运气）

    @Autowired
    private EmployeeRepositoryImp er;

和

    @Autowired
    private EmployeeRepository er;

以下是我的代码......

    package com.rw.examples.hibernate_ogm_neo4j;

    import javax.persistence.EntityManager;
    import javax.persistence.EntityManagerFactory;
    import javax.persistence.Persistence;

    import org.springframework.context.annotation.Bean;
    import org.springframework.context.annotation.Configuration;

    @Configuration
    public class AppConfig {

        @Bean
        public EntityManager entityManager() {
            return entityManagerFactory().createEntityManager();
        }

        @Bean
        public EntityManagerFactory entityManagerFactory() {
            return Persistence.createEntityManagerFactory("ogm-neo4j");
        }

    }



    package com.rw.examples.hibernate_ogm_neo4j;

    import org.springframework.data.jpa.repository.JpaRepository;
    import org.springframework.stereotype.Repository;

    @Repository
    public interface EmployeeRepository extends JpaRepository<Employee, Long>{

    }




    package com.rw.examples.hibernate_ogm_neo4j;

    import javax.persistence.EntityManager;

    import org.springframework.beans.factory.annotation.Autowired;
    import org.springframework.data.jpa.repository.support.SimpleJpaRepository;
    import org.springframework.stereotype.Repository;

    @Repository
    public class EmployeeRepositoryImp extends SimpleJpaRepository<Employee, Long> implements EmployeeRepository{

        private EntityManager entityManager;

        @Autowired
        public EmployeeRepositoryImp(Class<Employee> domainClass, EntityManager em) {
            super(domainClass, em);
            // TODO Auto-generated constructor stub
            this.entityManager = em;
        }
    }



    package com.rw.examples.hibernate_ogm_neo4j;

    import javax.persistence.EntityManager;
    import javax.persistence.EntityManagerFactory;

    import org.junit.Test;
    import org.springframework.beans.factory.annotation.Autowired;
    import org.springframework.context.ApplicationContext;
    import org.springframework.context.annotation.AnnotationConfigApplicationContext;
    import org.springframework.context.annotation.ComponentScan;
    import org.springframework.data.jpa.repository.config.EnableJpaRepositories;
    import org.springframework.stereotype.Controller;

    @Controller
    @EnableJpaRepositories (basePackages = {"com.rw.examples.hibernate_ogm_neo4j"})
    @ComponentScan(basePackages = {"com.rw.examples.hibernate_ogm_neo4j"})
    public class RepositoryTest {


    @Autowired
    private EmployeeRepositoryImp er;

    @Test
    public void testRepository() {

        ApplicationContext ctx = new AnnotationConfigApplicationContext(AppConfig.class);

        EntityManagerFactory emf = ctx.getBean(EntityManagerFactory.class);
        EntityManager em = emf.createEntityManager();


        System.out.println("testRepository");
        er.save(new Employee("Frank"));
        System.out.println("list employees using repository");
        Iterable<Employee> employees = er.findAll();
        employees.forEach(e->System.out.println(e.toString()));
    }
}

Answer 1

您不需要EmployeeRepository的具体实现。注释掉该类并自动装配EmployeeRepository。

此外，您不需要在测试中使用@Controller注释。

Answer 2

终于解决了问题。要运行JUNIT测试，需要使用@RunWith。

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(classes=AppConfig.class, loader = AnnotationConfigContextLoader.class)
public class RepositoryTest {...}

同样在AppConfig.java中需要有以下注释：

@Configuration
@EnableJpaRepositories
public class AppConfig {...}

最后，似乎hibernate ogm与jparepository不兼容。还在学习......

spring @Autowired存储库返回null

2 个答案: