SQL查询获取实际日期和日期时间差异

Question

我需要获得已经开始但尚未完成的旅程。到目前为止，我有这个。

//DepartureDate and Returndate are Datetime Types

    $sql = "SELECT * FROM Orders WHERE departureDate <= GETDATE() >= returndate";

Answer 1

假设您使用的是SQL Server，只需将逻辑分为两部分：

SELECT o.*
FROM Orders o
WHERE o.departureDate <= GETDATE() AND
      GETDATE() >= o.returndate

Answer 2

$sql = "SELECT * FROM Orders WHERE departureDate > GETDATE() AND returndate <= GETDATE()";