Question

我有一个包含月度信息的数组，如下所示：

[appr] => Array
            (
                [0] => Array
                    (
                        [month] => August
                        [approd] => 23
                    )

                [1] => Array
                    (
                        [month] => September
                        [approd] => 546
                    )

                [2] => Array
                    (
                        [month] => October
                        [approd] => 234
                    )

            )

我希望输出如下

[appr] => Array(
        August => 23,
        September => 546,
        October => 234
   )

任何人都可以帮助我使用php实现这一目标。

Answer 1

如果您正在寻找简单的单行解决方案，请使用array_column()和array_combine()函数。

试试这个：

$array['appr'] = array_combine(array_column($array['appr'], "month"), array_column($array['appr'], "approd"));

Answer 2

只需在array中循环并创建一个新数组

即可

$array = array(array('month'=>'August','approd'=>'23'),array('month'=>'September','approd'=>'56'),array('month'=>'October','approd'=>'234'),);
$new = array();
foreach($array as $val) {
   $new['appr'][$val['month']] = $val['approd'];
}

Answer 3

使用array_column函数的“单行”解决方案：

$arr['appr'] = array_column($arr['appr'], 'approd', 'month');

print_r($arr);

输出：

Array
(
    [appr] => Array
        (
            [August] => 23
            [September] => 546
            [October] => 234
        )
)

Answer 4

另一种选择是使用<div class="container"> <div class="box a"> </div> <div class="box b"> </div> <div class="box c"> </div> </div>：

array_walk_recursive

最后输出结果：

<?php

$array = array(
    0 => array(
        'something',
    ),
    1 => array(
        'else',
    )
);


// If the keys are unique
$newArray = array();
array_walk_recursive($array, function($v, $k) use (&$newArray) {
    $newArray[$k] = $v;
});

// If you have duplicate keys
$newArray = array();
array_walk_recursive($array, function($v) use (&$newArray) {
    $newArray[] = $v;
});

资源

array_walk_recursive - Manual

Php多维数组转换为一维

4 个答案:

资源