在单独的一行上打印10个范围内的素数

Question

我想为每10个输入分离程序的输出（打印）。代码是找到从1到n的素数和它们的中位数。

我只想将每10个n的打印分开：

primes from  1 to 10:
       from 10 to 20:
       from 20 to 30:

你能帮帮我吗？

#include <stdio.h>

int main()
{
    int n, x, y, p, sum, sumx;
    float arm;
    sum = 0, sumx = 0;
    printf("\n Enter the maximum value of n =");
    scanf("%d", &n);
    printf("\n All prime numbers from 1 to %d are: ", n);

    for (x = 2; x <= n; x++)
    {
        p = 1;
        for (y = 2; y <= x / 2; y++)
        {
            if (x % y == 0)
            {
                p = 0;
                break;
            }
        }
        if (p == 1)
        {
            sum += x;
        }
        if (p == 1 && x != 1)
        {
            printf("%d ", x);
            sumx++;
            arm = (sum * 1.0) / sumx;
        }
    }

    printf("\nThe sum of all Prime numbers from 1 to %d =%d", n, sum);
    printf("\nTotal prime numbers is %d", sumx);
    printf("\nThe median of all Prime numbers from 1 to %d is %.2f", n, arm);

    return 0;
}

Answer 1

你可以打印出＃34;从_到_：＆＃34;每当你达到x可被10整除的值时：

#include <stdio.h>

int main()
{
    int n, x, y, p, sum, sumx;
    float arm;
    sum = 0, sumx = 0;
    printf("\n Enter the maximum value of n =");
    scanf("%d", &n);
    printf("\n All prime numbers from 1 to %d are: ", n);
    int upper = n < 10? n : 10;
    printf("\nFrom 1 to %d: ", upper);

    for (x = 2; x <= n; x++)
    {
        p = 1;
        for (y = 2; y <= x / 2; y++)
        {
            if (x % y == 0)
            {
                p = 0;
                break;
            }
        }
        if (p == 1)
        {
            sum += x;
        }
        if (p == 1 && x != 1)
        {
            printf("%d ", x);
            sumx++;
            arm = (sum * 1.0) / sumx;
        }

        if (x % 10 == 0 && x != n) {
            int upper = (x + 10) > n? n : (x + 10);
            printf("\nFrom %d to %d: ", x + 1, upper);
        }   
    }

    printf("\nThe sum of all Prime numbers from 1 to %d =%d", n, sum);
    printf("\nTotal prime numbers is %d", sumx);
    printf("\nThe median of all Prime numbers from 1 to %d is %.2f", n, arm);

    return 0;
}

这会产生如下输出：

  

输入最大值n = 29

     

从1到29的所有素数都是：

     

从1到10：2 3 5 7

     

从11到20：11 13 17 19

     

从21到29：23 29

     

所有素数的总和从1到29 = 129

     

总素数为10

     

从1到29的所有Prime数的中值是12.90

Answer 2

我无法清楚地理解你的问题，但是如果你想分开10到20或20到30之间的素数的行，那么你可以在你的循环中添加它

if(x%10 == 0)
    printf("\n");

或者，如果你想在一行中想要10个素数，那么

if(sumx%10 == 0)
    printf("\n");