Question

我需要加入四个表并从中查询数据。我尝试了以下SQL查询来获取四个表中的数据

SELECT tbl_user.vFirst,tbl_user.vLast,tbl_feed.dCreatedDate,tbl_feed.tModifyDate,tbl_feed.fAddress, tbl_feed.tAddress,tbl_ratings.rate,tbl_ratings.comment,vCost
FROM tbl_feed
INNER JOIN tbl_user ON tbl_user.iUserID = tbl_feed.iUserID
INNER JOIN tbl_ratings ON tbl_ratings.trip_id = tbl_feed.iFeedID
INNER JOIN tbl_feed.iFeedID=tbl_nearest_drivers.iFeedID;

但是在运行上面的查询时。

错误1064（42000）：您的SQL语法有错误;检查手册，对应右边的MySQL服务器版本在＆＃39; .iFeedID＆＃39;附近使用的语法在第1行

为什么这个JOIN不起作用？

Answer 1

试试这个。

SELECT tbl_user.vFirst,tbl_user.vLast,tbl_feed.dCreatedDate,tbl_feed.tModifyDate,tbl_feed.fAddress, tbl_feed.tAddress,tbl_ratings.rate,tbl_ratings.comment,vCost
FROM tbl_feed
INNER JOIN tbl_user ON tbl_user.iUserID = tbl_feed.iUserID
INNER JOIN tbl_ratings ON tbl_ratings.trip_id = tbl_feed.iFeedID
INNER JOIN tbl_feed ON tbl_feed.iFeedID=tbl_nearest_drivers.iFeedID;

Answer 2

希望此查询可以帮助您解决问题。在您的查询中，INNER JOIN错过了表名tbl_nearest_drivers。

     SELECT
        tbl_user.vFirst,
        tbl_user.vLast,
        tbl_feed.dCreatedDate,
        tbl_feed.tModifyDate,
        tbl_feed.fAddress,
        tbl_feed.tAddress,
        tbl_ratings.rate,
        tbl_ratings.`comment`,
        vCost
    FROM
        tbl_feed
    INNER JOIN tbl_user ON tbl_user.iUserID = tbl_feed.iUserID
    INNER JOIN tbl_ratings ON tbl_ratings.trip_id = tbl_feed.iFeedID
    INNER JOIN tbl_nearest_drivers ON tbl_feed.iFeedID = tbl_nearest_drivers.iFeedID;

Answer 3

您忘了在上次加入中说明表名：

SELECT tbl_user.vFirst,tbl_user.vLast,tbl_feed.dCreatedDate,tbl_feed.tModifyDate,tbl_feed.fAddress, tbl_feed.tAddress,tbl_ratings.rate,tbl_ratings.comment,vCost
FROM tbl_feed
INNER JOIN tbl_user ON tbl_user.iUserID = tbl_feed.iUserID
INNER JOIN tbl_ratings ON tbl_ratings.trip_id = tbl_feed.iFeedID
INNER JOIN tbl_nearest_drivers ON tbl_feed.iFeedID=tbl_nearest_drivers.iFeedID;

Answer 4

SELECT tbl_user.vFirst,tbl_user.vLast,tbl_feed.dCreatedDate,tbl_feed.tModifyDate,tbl_feed.fAddress, tbl_feed.tAddress,tbl_ratings.rate,tbl_ratings.comment,vCost
FROM tbl_feed
INNER JOIN tbl_user ON tbl_user.iUserID = tbl_feed.iUserID
INNER JOIN tbl_ratings ON tbl_ratings.trip_id = tbl_feed.iFeedID
INNER JOIN tbl_nearest_drivers ON tbl_feed.iFeedID=tbl_nearest_drivers.iFeedID;

我想你觉得如此？

INNER JOIN SQL上的四个表制作错误

4 个答案: