Question

我在这里查看了大多数正则表达式的问题，但没有一个与我的具体情况相符。

说我有一个字符串："ABe(CD)(EF)GHi"

我想："A", "Be", "(CD)", "(EF)", "G", "Hi"

我试过了：

.split("(?=[A-Z\\(\\)])"), which gives me: "A", "Be", "(", "C", "D", ")", "(", "E", "F", ")", "G", "Hi".

有什么想法吗？

Answer 1

试试这个：

String input = "ABe(CD)(EF)GHi";

String[] split = input.split("(?=[A-Z](?![^(]*\\)))|(?=\\()|(?<=\\))");
System.out.println(Arrays.toString(split));

输出

[A, Be, (CD), (EF), G, Hi]

解释

 (?=              Before:
    [A-Z]           Uppercase letter
    (?![^(]*\))       not followed by ')' without first seeing a '('
                      i.e. not between '(' and ')'
 )
|(?=              or before:
    \(              '('
 )
|(?<=             or after:
     \)             ')'
 )

Answer 2

试试这个..

String array = "ABe(CD)(EF)GHi";
int i = 0;

for(int j=0; j<array.length();)
{
   if(Character.isUpperCase(array.charAt(i)))
   {
       j++;
       System.out.println(array.substring(i, i+1));
      if(Character.isUpperCase(array.charAt(i+1)))
      {   System.out.println(array.substring(i+1, i+3));
          i = i+3;
          j = j + 3;
      }
  }
  else
  {
      System.out.println(array.substring(i+1, i+3));
      i = i+4;
      j = j + 3;
  }
}

Answer 3

匹配而不是拆分。

String s = "ABe(CD)(EF)GHi";
Pattern regex = Pattern.compile("\([^()]*\)|[A-Z][a-z]+|[A-Z]");
Matcher matcher = regex.matcher(s);
while(matcher.find()){
        System.out.println(matcher.group(0));
}

DEMO

用括号拆分字符串，用括号分组，java

3 个答案: