如何使用sqlalchemy按日期过滤

时间:2017-01-05 17:30:39

标签: python mysql sql sqlalchemy

导入模块后:

import datetime, uuid
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import scoped_session, sessionmaker
from sqlalchemy import Column, ForeignKey, Integer, String, DateTime, create_engine, literal

我继续连接到db:

Base = declarative_base()
session = scoped_session(sessionmaker())
engine = create_engine('mysql://root:pass@localhost/testdb', echo=False)
session.remove()
session.configure(bind=engine, autoflush=False, expire_on_commit=False)

我定义并创建了MyObject的表:

class MyObject(Base):
    __tablename__ = 'myobjects'
    uuid = Column(String(64), primary_key=True, unique=True)
    created = Column(DateTime, nullable=False) 

    def __init__ (self, *args, **kwargs):
        self.uuid = str(uuid.uuid4()).replace('-','').lower()
        self.created = datetime.datetime.utcnow()

Base.metadata.create_all(engine)

我创建了10个MyObject个实体:

for i in range(10):
    obj = MyObject()
    session.add(obj)
    session.commit()

我通过打印创建的日期来查询所有实体:

objects = session.query(MyObject).all()
for obj in objects:
    print obj.created

打印:

2017-01-05 17:22:21
2017-01-05 17:22:21
.
.
.
2017-01-05 17:22:43

问题:

如何通过仅过滤那些未在'2017-01-05 17:22:43'上创建的实体进行查询?

我试过这个:

result = session.query(MyObject).filter(MyObject.created!='2017-01-05 17:22:43').all()

但它会返回所有过滤任何内容的对象......

1 个答案:

答案 0 :(得分:2)

要比较datetimes,您需要将string转换为datetime个对象。对于例如要将字符串2016-10-20转换为datetime,您可以这样做:

from datetime import datetime
print datetime.strptime('2016-10-20', '%Y-%m-%d')

对于您的问题,如果您要检查列created是否与时间2017-01-05 17:22:43不匹配,那么我们首先在查询中转换为datetime对象:

from datetime import datetime
search_created = datetime.strptime('2017-01-05 17:22:43', '%Y-%m-%d %H:%M:%S')
result = session.query(MyObject).filter(MyObject.created!=search_created).all()

您可以在strftimestrptime上查看有关here的更多信息。

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