如何在SQL中选择具有重复列值的所有行

Question

我在col1中有一些重复的表：

co1, col2, col3
a, d, f
r, h, d
e, g, h
z, k, m
e, s, t
a, b, c
e, k, t

感谢this post，我可以选择重复的所有col1值

SELECT col1
FROM mytable
GROUP BY col1
HAVING ( COUNT(col1) > 1 )

如何选择具有重复col1值的所有行并按col1排序？预期结果如下：

co1, col2, col3
a, d, f
a, b, c
e, g, h
e, s, t
e, k, t

Answer 1

使用EXISTS

SELECT *
FROM   mytable a
WHERE  EXISTS (SELECT 1
               FROM   mytable b
               WHERE  a.col1 = b.col1
               HAVING Count(col1) > 1) 
Order by col1

另一种方式

SELECT *
FROM   (SELECT *,
               Count(1)OVER( partition BY col1) AS cnt
        FROM   mytable) a
WHERE  cnt > 1
ORDER  BY col1 

Answer 2

您可以使用窗口功能：

select co1, col2, col3
from (
  select co1, col2, col3, count(*) over (partition by col1) as cnt
  from the_table
) t
where cnt > 1
order by col1;

Answer 3

您可以使用原始表Inner Join结果select t1.* from your_table t1 inner join ( select col1 from your_table group by col1 having count(col1) > 1 ) t2 on t1.col1 = t2.col1 order by t1.col1; ：

{{1}}

Answer 4

Select * 
From ( Select * ,count(*) over (Partition By Col1) as cnt from t) t
Where cnt>1

Answer 5

        Select co1,col2,col3 From 
    ( Select * ,count(*) over (Partition By Co1) as cnt from #b) a
 Where cnt>1