Question

我有一个像这样的SQL表：

ID    NR    Status
1     510     2
2     510     2
3     510     2
.     ...     .
17    987     2
33    987     3
35    987     2

我想得到那张桌子; 如果 NR 列具有相同的值且状态列具有不同的值。所以，我想得到包含17,33和35行的表。

我试试这个，但它不起作用：

select * from table1 as t1
inner join table1 t2 ON t1.NR=t2.NR and t1.Status != t2.Status

Answer 1

使用窗口函数：

select 
    *
from
    your_table
having
    count(distinct status) over (partition by nr) > 1;

窗口功能v2：

select * from
(select 
    t.*,
    count(distinct status) over (partition by nr) cnt
from
    your_table t
) t where cnt > 1;

使用联接：

select t1.*
from your_table t1
inner join (
    select nr
    from your_table
    group by nr
    having count(distinct status) > 1
) t2 on t1.nr = t2.nr;

使用IN：

select *
from your_table t1
where nr in (
    select nr
    from your_table
    group by nr
    having count(distinct status) > 1
);

使用存在：

select *
from your_table t1
where exists (
    select 1
    from your_table t2
    where t2.nr = t1.nr
    and t1.status <> t2.status
);

Answer 2

select 
    *
from
    table
where
    count(distinct status) over (partition by nr) > 1;

查找列上存在差异的类似行

2 个答案: