将结构指针添加到指针数组

时间:2017-01-09 19:35:16

标签: c arrays pointers struct

我遇到了问题,我真的不知道该怎么做。

我试图将“新学生”插入学生阵列。该数组包含指向已创建结构的指针。有人能找到错误吗?它将学生结构添加到阵列中,但尤其是打印不起作用。

如果有人可以帮助我,那将非常有帮助。 :) PS:你可以复制代码。

这是我的代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_HASH 10
typedef struct student
{
    unsigned int matnr;
    char *name;
    struct student *next_student;
} Student;

Student **hash_tabelle[MAX_HASH];

void insert_student (unsigned int matnr, char *name)
{
    Student *neuer_student = malloc(sizeof(Student));
    neuer_student->name = malloc(sizeof(*name)+1);
    neuer_student->matnr = matnr;
    strcpy(neuer_student->name, name);
    neuer_student->next_student = NULL;

    // Index im Hash-Array ermitteln
    int hash_index = matnr % 10;

    if(hash_tabelle[hash_index] == NULL)
    {
        neuer_student->next_student = hash_tabelle[hash_index];
        hash_tabelle[hash_index] = neuer_student;
    }
    else
    {      
        while(*hash_tabelle[hash_index] != NULL && (((*hash_tabelle[hash_index])->matnr - neuer_student->matnr) <= 0))
            hash_tabelle[hash_index] = &(*hash_tabelle[hash_index])->next_student;
        neuer_student->next_student = *hash_tabelle[hash_index];
        *hash_tabelle[hash_index] = neuer_student;
    }
}

void print_hash_tabelle()
{
    for(int i = 0; i != MAX_HASH - 1; i++){
        printf("%d)\t", i);

        hash_tabelle[i] = &(*hash_tabelle[i])->next_student;

        for(; hash_tabelle[i] != NULL; hash_tabelle[i] = &(*hash_tabelle[i])->next_student){
            printf("%s (%d)", (&(*hash_tabelle[i])->name), (&(*hash_tabelle[i])->matnr));
        }
        printf("\t");
    }
}

int main()
{
    unsigned int matnr;
    char name[100];

    do
    {
        printf("Matrikelnummer:\t");
        scanf("%d", &matnr);
        fflush(stdin);
        getchar(); // um das \n aus dem Puffer zu kriegen und rauszuschmeißen
        printf("Name:\t\t");
        fgets(name, 30, stdin);
        insert_student(matnr, name);
    }
    while (matnr != 0);

    print_hash_tabelle();

    return 0;
}

2 个答案:

答案 0 :(得分:1)

使用哈希表非常简单......不需要对固定大小的链表指针数组使用解除引用。

第1步 - 哈希表是链表列表指针的数组。

  

正如@BLUEPIXY建议:

Student *hash_tabelle[MAX_HASH];

第2步 - 分配并释放每个链表,将每个项初始化为NULL。

  

否则,if(hash_tabelle[hash_index] == NULL)未定义   函数insert_student()中的行为。

void hash_init()
{
    for(int i=0;i<MAX_HASH;i++) {
        hash_tabelle[MAX_HASH]=NULL;
    }
}

第3步 - 分配足够的字符以将char *name存储到insert_student()

  

正如@ WhozCraig建议的那样,使用strlen()

void insert_student (unsigned int matnr, char *name)
{
    Student *neuer_student = malloc(sizeof(Student));
    neuer_student->name = malloc(strlen(name)+1);
    neuer_student->matnr = matnr;
    strcpy(neuer_student->name, name);
    neuer_student->next_student = NULL;

第4步 - 在neuer_student(函数hash_tabelle[])中添加insert_student()

  

警告:索引应包含在数组的大小中   [0..MAX_HASH [。 (使用10代替MAX_HASH可能会成为错误。

int hash_index = matnr % MAX_HASH;
  

hash_tabelle[hash_index]为NULL时,简单存储   neuer_student。无需修改neuer_student->next_student

if(hash_tabelle[hash_index] == NULL)
{
    hash_tabelle[hash_index] = neuer_student;
}
  

否则,请浏览要存储的hash_tabelle[hash_index]链接列表   最后的neuer_student

else
{
    Student *tmp;

    tmp = hash_tabelle[hash_index];
    while (tmp->next_student!=NULL) {
        tmp = tmp->next_student;
    }
    tmp->next_student = neuer_student;
}

第5步 - 打印哈希表的所有项目(函数print_hash_tabelle()

  

重用相同的方法来探索每个链表指针。

     

警告:浏览从0MAX_HASH-1

的所有项目
void print_hash_tabelle()
{
    for(int i = 0; i < MAX_HASH; i++){ // ERR != MAX_HASH - 1; i++){
        printf("%d)\t", i);
        Student *tmp = hash_tabelle[i];
        while (tmp!=NULL) {
             printf("%s (%d)", tmp->name, tmp->matnr);
            tmp = tmp->next_student;
        }
        printf("\n");
    }
}

第6步 - 释放hash_tabelle[]每个项目的记忆。

  
      
  1. 释放分配的字符串free(tmp->name);
  2.   
  3. 删除当前学生hash_tabelle[i] = tmp->next_student;
  4.   
  5. 释放已分配的学生free(tmp);
  6.   
  7. 重复直到链表的末尾
  8.   

全部(main()除了在结尾处添加对hash_free()的调用之外没有变化)。

void hash_free()
{
    for(int i=0;i<MAX_HASH;i++) {
        Student *tmp = hash_tabelle[i];
        while (tmp!=NULL) {
            free(tmp->name);
            hash_tabelle[i] = tmp->next_student;
            free(tmp);
            tmp = hash_tabelle[i];
        }
    }
}

答案 1 :(得分:0)

像这样:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define MAX_HASH 10

typedef struct student {
    unsigned int matnr;
    char *name;
    struct student *next_student;
} Student;

Student *hash_tabelle[MAX_HASH];

void insert_student (unsigned int matnr, char *name){
    Student *neuer_student = malloc(sizeof(Student));
    neuer_student->name = malloc(strlen(name)+1);
    strcpy(neuer_student->name, name);
    neuer_student->matnr = matnr;
    //neuer_student->next_student = NULL;

    int hash_index = matnr % MAX_HASH;
    Student head = { .next_student = hash_tabelle[hash_index] };
    Student *prev = &head, *curr = head.next_student;
    while(curr != NULL && curr->matnr <= neuer_student->matnr){
        prev = curr;
        curr = curr->next_student;
    }
    neuer_student->next_student = curr;
    prev->next_student = neuer_student;
    hash_tabelle[hash_index] = head.next_student;
}

void print_hash_tabelle(void){
    for(int i = 0; i < MAX_HASH; i++){
        printf("%d)\t", i);
        for(Student *p = hash_tabelle[i]; p; p = p->next_student){
            printf("%s (%d)\t", p->name, p->matnr);
        }
        printf("\n");
    }
}

void free_hash_tabelle(void){
    for(int i = 0; i < MAX_HASH; i++){
        Student *p = hash_tabelle[i];
        while(p){
            Student *temp = p->next_student;
            free(p->name);
            free(p);
            p = temp;
        }
    }
}

int main(void){
    int matnr = -1;//for %d of scanf
    char name[100];

    while(1){
        printf("Matrikelnummer(-1 for end input): ");fflush(stdout);
        scanf("%d", &matnr);
        if(matnr < 0)
            break;
        while(getchar() != '\n');
        printf("Name: ");fflush(stdout);
        fgets(name, sizeof name, stdin);
        name[strcspn(name, "\n")] = 0;
        insert_student(matnr, name);
    }

    print_hash_tabelle();
    free_hash_tabelle();

    return 0;
}