Question

我一直在搜索Stack Overflow，但无法找到正确的代码来纠正，例如。

bibliographystyle{apa}

分为：

\begin{document}

The body of the document goes here...

\newpage

\bibliography{bibliography} % Or whatever you decided to call your .bib file 

\usepackage[round, comma, sort&compress ]{natbib} 

bibliographystyle{apa}
\end{document}

Answer 1

使用正则表达式以标点字符分割
在句子开头用大写字母加入所有内容。

例如：

import re
text = 'hello! are you tired? no, not at all!'

punc_filter = re.compile('([.!?]\s*)')
split_with_punctuation = punc_filter.split(text)

final = ''.join([i.capitalize() for i in split_with_punctuation])
print(final)

输出：

>>> Hello! Are you tired? No, not at all!

Answer 2

您可以尝试这种正则表达式方法：

import re
re.sub("(^|[.?!])\s*([a-zA-Z])", lambda p: p.group(0).upper(), s)
# 'Hello! Are you tired? No, not at all!'

(^|[.?!])匹配字符串^或.?!的开头，后跟可选空格;
[a-zA-Z]在第一个模式后直接匹配字母;
使用lambda函数将捕获的组转换为大写;

Answer 3

您可以执行类似

的操作

x = "hello! are you tired? no, not at all!"
y = x.split("? ")
z="" 
for line in y:
    z = "{} {}".format(z,line.capitalize())
print(z)

根据您的需要进行调整。

Answer 4

capitalize（）方法使除第一个字母外的所有字母变小。

更一般的变体是：

def capitalize(text):
    punc_filter = re.compile('([.!?;]\s*)')
    split_with_punctuation = punc_filter.split(text)
    for i,j in enumerate(split_with_punctuation):
        if len(j) > 1:
            split_with_punctuation[i] = j[0].upper() + j[1:]
    text = ''.join(split_with_punctuation)
    return text

text = "hello Bob! are you tired? no, not at all!"
capitalize(text)

输出：

'Hello Bob! Are you tired? No, not at all!'

'。'，'！'之后的大写字母和'？'用Python签名

4 个答案: