如何将以下存储过程转换为准备好的语句?

时间:2017-01-18 17:58:45

标签: mysql stored-procedures prepared-statement sql-function

以下存储过程仅接受显式写出实数的参数。例如:CALL test11(46)

我希望它重写,以便它可以接受类似于以下内容:

SELECT *, CALL test11(vendor_id) FROM vendors;

或者

CALL test11(SELECT vendor_id FROM vendors WHERE vendor_name = 'Micro Center');

我理解第一个/前一个是没有意义的,因为可以实现IF语句而不必求助于存储过程。但我发现后者非常重要。

存储过程语法:

DELIMITER //
CREATE PROCEDURE test11(IN vendor_id_var INT)
BEGIN
    DECLARE sum_balance_due_var DECIMAL(9, 2);

    SELECT SUM(invoice_total - payment_total - credit_total)
    INTO sum_balance_due_var 
    FROM invoices i
    JOIN vendors v ON v.vendor_id = i.vendor_id
    WHERE i.vendor_id = vendor_id_var
    GROUP BY i.vendor_id, vendor_name;

    IF sum_balance_due_var > 0 THEN
        SELECT CONCAT('Balance due: $', sum_balance_due_var) AS message;
    ELSE
        SELECT 'Balance paid in full' AS message;
    END IF;
END//
DELIMITER ;

供应商表:

CREATE TABLE vendors (
    vendor_id INT(11) NOT NULL AUTO_INCREMENT,
    vendor_name VARCHAR(50) NOT NULL,
   -- other columns
)

发票表:

CREATE TABLE invoices (
    invoice_id INT(11) NOT NULL AUTO_INCREMENT,
    vendor_id INT(11) NOT NULL,
    invoice_total DECIMAL(9,2) NOT NULL,
    payment_total DECIMAL(9,2) NOT NULL DEFAULT '0.00',
    credit_total DECIMAL(9,2) NOT NULL DEFAULT '0.00',
    -- other columns
)

一些示例数据:

INSERT INTO vendors (vendor_id, vendor_name) VALUES (34, 'IBM');
INSERT INTO vendors (vendor_id, vendor_name) VALUES (37, 'Blue Cross');
INSERT INTO invoices (invoice_id, vendor_id, invoice_total, payment_total, credit_total) VALUES (19, 34, 116.54, 116.54, 0.00);
INSERT INTO invoices (invoice_id, vendor_id, invoice_total, payment_total, credit_total) VALUES (52, 34,1083.58,1083.58, 0.00);
INSERT INTO invoices (invoice_id, vendor_id, invoice_total, payment_total, credit_total) VALUES (46, 37, 224.00, 224.00, 0.00);
INSERT INTO invoices (invoice_id, vendor_id, invoice_total, payment_total, credit_total) VALUES (50, 37, 116.00, 116.00, 0.00);
INSERT INTO invoices (invoice_id, vendor_id, invoice_total, payment_total, credit_total) VALUES (113, 37,224.00,   0.00, 0.00);

1 个答案:

答案 0 :(得分:1)

将其定义为FUNCTION

CREATE FUNCTION test11(IN vendor_id_var INT)
RETURNS text -- or whatever type you want returned
BEGIN
    -- your existing code

    RETURN <something>
END

并删除单词CALL

SELECT *, test11(vendor_id)
FROM vendors

这是一个UDF,就像使用内置一样。

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