Question

如何将此字符串转换为MST时区datetime对象？

>>> type(date_str)
<type 'str'>
>>> date_str
'2017-01-17T20:02:45.767Z'

Answer 1

这是符合EnvelopeRecipients: update method.标准的字符串。有各种ISO 8601这个。但要将其与时区转换相结合，您可以：

import datetime as dt
from pytz import timezone

def convert_my_iso_8601(iso_8601, tz_info):
    assert iso_8601[-1] == 'Z'
    iso_8601 = iso_8601[:-1] + '000'
    iso_8601_dt = dt.datetime.strptime(iso_8601, '%Y-%m-%dT%H:%M:%S.%f')
    return iso_8601_dt.replace(tzinfo=timezone('UTC')).astimezone(tz_info)

my_dt = convert_my_iso_8601('2017-01-17T20:02:45.767Z', timezone('MST'))

Answer 2

这是一个 Python 3.9 选项，仅使用标准库：

from datetime import datetime
from zoneinfo import ZoneInfo

date_str = '2017-01-17T20:02:45.767Z'

# to datetime, UTC:
dt = datetime.fromisoformat(date_str.replace('Z', '+00:00'))

# to mountain standard time:
dt_mountain = dt.astimezone(ZoneInfo("America/Denver"))

print(dt_mountain.isoformat())
# 2017-01-17T13:02:45.767000-07:00

对于旧版本，使用 GitHub issue #14903 的不同方法：

from datetime import datetime
import dateutil

date_str = '2017-01-17T20:02:45.767Z'

# to datetime, UTC:
dt = dateutil.parser.parse(date_str)

# to mountain standard time:
dt_mountain = dt.astimezone(dateutil.tz.gettz("America/Denver"))

print(dt_mountain.isoformat())
# 2017-01-17T13:02:45.767000-07:00

将zulu时间字符串转换为MST日期时间对象

2 个答案: