C2106:' =' :左操作数必须是l值

时间:2017-01-18 18:55:27

标签: c operand

所以,我将C语言作为我的第一语言,并且在练习时进行了一些编码,我得到了上面的错误。我按照书中的说法完成了所有工作(Stephen G. Kochan:C编程,第三版)。 我究竟做错了什么? 我正在使用Microsoft Visual Studio 2015。

感谢您的帮助! 标记

struct date
{
int month;
int day;
int year;
};

int main(void)
{
    struct date today, tomorrow;
    int numberOfDays(struct date d);

    printf("Adja meg a mai datumot (hh nn eeee): ");
    scanf_s("%i%i%i", &today.month, &today.day, &today.year);

    if (today.day != numberOfDays(today))
    {
        tomorrow.day = today.day + 1;
        tomorrow.month = today.month;
        tomorrow.year = today.year;
    }
    else if (today.month == 12)
    {
        tomorrow.day = 1;
        tomorrow.month = 1;
        tomorrow.year = today.year + 1;
    }
    else
    {
        tomorrow.day = 1;
        tomorrow.month = today.month + 1;
        tomorrow.year = today.year;
    }
    printf("A holnapi datum: %i/%i/%.2i.\n", tomorrow.month, tomorrow.day, tomorrow.year % 100);

    return 0;
}

int numberOfDays(struct date d)
{
    int days;
    bool isLeapYear(struct date d);
    const int daysPerMonth[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };

    if (isLeapYear(d) == true && d.month == 2)
        days = 29;
    else
        days = daysPerMonth[d.month - 1];

    return days;
}

bool isLeapYear(struct date d)
{
    bool leapYearFlag;

    if ( (d.year % 4 == 0 && d.year % 100 = 0) || d.year % 400 == 00) //The error shows up here
        leapYearFlag = true;
    else
        leapYearFlag = false;

    return leapYearFlag;
}

1 个答案:

答案 0 :(得分:1)

这是一个拼写错误

if ( (d.year % 4 == 0 && d.year % 100 = 0) || d.year % 400 == 00) 
                                    ^^^^

我认为你的意思是

if ( (d.year % 4 == 0 && d.year % 100 != 0) || d.year % 400 == 00) 
                                     ^^^^

00相当于0。:)

该功能可以写得更简单

bool isLeapYear( struct date d )
{
    return ( d.year % 4 == 0 && d.year % 100 != 0 ) || ( d.year % 400 == 0 );
}