str在python中的时间

Question

time1 = "2010-04-20 10:07:30"
time2 = "2010-04-21 10:07:30"

如何将上述字符串转换为时间戳？

我需要减去上面的时间戳time2-time1。

Answer 1

对于Python 2.5 +

from datetime import datetime
format = '%Y-%m-%d %H:%M:%S'
print datetime.strptime(time2, format) - 
        datetime.strptime(time1, format)
# 1 day, 0:00:00

适用于Python 2.4的

编辑

import time
format = '%Y-%m-%d %H:%M:%S'
print time.mktime(time.strptime(time2, format)) - 
        time.mktime(time.strptime(time1, format))
# 86400.0

Answer 2

如果你像我一样坚持使用Python 2.4系统：

from time import strptime
from datetime import datetime

str_to_datetime = lambda st: datetime(*strptime(st, '%Y-%m-%d %H:%M:%S')[:6])

str_to_datetime('2010-04-20 10:07:30')

否则datetime.strptime（）会正常工作。

Answer 3

>>> t1 = datetime.strptime(time1, "%Y-%m-%d %H:%M:%S")
>>> t2 = datetime.strptime(time2, "%Y-%m-%d %H:%M:%S")
>>> t2-t1
datetime.timedelta(1)

>>> (t2-t1).days
1
>>> (t2-t1).seconds
0

Answer 4

import time

time1 = "2010-04-20 10:07:30"

time_tuple = time.strptime(time1, "%Y-%m-%d %H:%M:%S")

timestamp = time.mktime(time_tuple)