将函数绑定到键不起作用

时间:2017-01-25 10:00:46

标签: python python-3.x tkinter key-bindings

我的代码:

import tkinter

master = tkinter.Tk()
master.title("test1")
master.geometry("300x300")

masterFrame = tkinter.Frame(master)

masterFrame.pack(fill=tkinter.X)

checkboxArea = tkinter.Frame(masterFrame, height=26)

checkboxArea.pack(fill=tkinter.X)

inputStuff = tkinter.Frame(masterFrame)

checkboxList = []

def drawCheckbox():
    checkboxList.append(entry.get())
    entry.delete(0,tkinter.END)
    checkboxRow = tkinter.Frame(checkboxArea)
    checkboxRow.pack(fill=tkinter.X)
    checkbox1 = tkinter.Checkbutton(checkboxRow, text = checkboxList[-1])
    checkbox1.pack(side=tkinter.LEFT)
    deleteItem = tkinter.Button(checkboxRow, text = "x", command=checkboxRow.destroy, bg="red", fg="white", activebackground="white", activeforeground="red")
    deleteItem.pack(side=tkinter.RIGHT)

def bindToEnter():
    master.bind('<Return>', drawCheckbox)

def createInputStuff():
    paddingFrame = tkinter.Frame(inputStuff, height=5)
    paddingFrame.pack(fill=tkinter.X)
    buttonDone.pack()
    inputStuff.pack()
    buttonAdd.pack_forget()
    bindToEnter()

def removeInputStuff():
    inputStuff.pack_forget()
    buttonAdd.pack()
    buttonDone.remove()

buttonDone = tkinter.Button(inputStuff, text = "Close Input", command=removeInputStuff)


buttonAdd = tkinter.Button(masterFrame, text="Add Item", command=createInputStuff)
buttonAdd.pack()


topInput = tkinter.Frame(inputStuff)
bottomInput = tkinter.Frame(inputStuff)

topInput.pack()
bottomInput.pack()

prompt = tkinter.Label(topInput, text="What do you want your checkbox to be for?")
prompt.pack()
entry = tkinter.Entry(bottomInput, bd=3)
entry.pack(side=tkinter.LEFT)
buttonConfirm = tkinter.Button(bottomInput, text="Confirm", command=drawCheckbox)
buttonConfirm.pack(side=tkinter.LEFT)

master.mainloop()

我们的想法是按下Return / Enter,然后点击“确认”按钮,运行drawCheckbox。这仍然是一项正在进行中的工作,当运行removeInputStuff时,我将从Enter键取消绑定drawCheckbox函数。尽管如此,我仍然不明白为什么按Enter键不会运行它所绑定的功能。

1 个答案:

答案 0 :(得分:1)

当您将函数fct绑定到键(或任何其他类型的事件)时,将使用一个参数调用该函数,例如fct(event)event具有各种属性,具体取决于事件的类型(鼠标位置,......)。您的问题是您调用drawCheckbox的函数不带任何参数,因此每次按Enter键都会引发错误

  

TypeError:drawCheckbox()获取0个位置参数,但是给出了1个

要纠正它,您可以使用默认参数

定义您的函数
def drawCheckbox(event=None):
    ...

或者你可以使用lambda函数来进行绑定

master.bind('<Return>', lambda event: drawCheckbox())