Question

Angular 2 - 当我在模块

中提供服务时如何将参数传递给抽象服务

带抽象服务的文件

@Injectable()
export class Service<T>{
    private headers: RequestOptions = headersRequest.options;
    private readonly baseUrl: string;

    constructor(private http: Http, baseUrl: string) {
        this.baseUrl = baseUrl;
    }

    public getAll(): Promise<T[]> {
        return this.http.get(`${this.baseUrl}`)
            .toPromise()
            .then(this.extractData)
            .catch(this.handleError);
    }

    public get(id: number): Promise<T> {
        return this.http.get(`${this.baseUrl}`)
            .toPromise()
            .then(this.extractData)
            .catch(this.handleError);
    }

    private extractData(res: Response) {
        let body = res.json();
        return body || {};
    }

    private handleError(error: Response | any) {
        let errMsg: string;
        if (error instanceof Response) {
            const body = error.json() || '';
            const err = body.error || JSON.stringify(body);
            errMsg = `${error.status} - ${error.statusText || ''} ${err}`;
        } else {
            errMsg = error.message ? error.message : error.toString();
        }
        console.error(errMsg);
        return Promise.reject(errMsg);
    }
}

我提供服务时带模块的文件

@NgModule({
    imports: [
        SharedModule,
        RouterModule.forChild(routes)
    ],
    declarations: [
        HeaderTennisComponent,
        TennisComponent,
        ProgramsComponent,
        ProgramComponent,
        PlotsComponent,
        GuidesComponent,
        CategoriesComponent,
        ChampionsComponent
    ],
    providers: [Service]
})

使用服务时带有组件的文件。

export class ProgramComponent implements OnInit {
    private program: IProgram;
    constructor(private route: ActivatedRoute, private tennisService: Service<IProgram>) {
        //
    }

    public ngOnInit() {
        this.getProgram(+this.route.snapshot.params['id']);
    }

    private getProgram(id: number) {
        this.tennisService.get(id).then(
            (program) => this.program = program
        );
    }
}

我提供服务时需要传递baseUrl。

Answer 1

Angular DI不直接支持泛型。

根据您的要求，有几种方法可以解决：

providers: [
  {provide: 'baseUrl': useValue: 'http://example.com'},
  {provide: Service, useFactory: (http, baseUrl) new Service<IProgram>(http, baseUrl), deps: [Http, new Inject('baseUrl') },
  {provide: 'ServiceIProgram', useFactory: (http, baseUrl) new Service<IProgram>(http, baseUrl), deps: [Http, new Inject('baseUrl') },
  {provide: 'Service', useFactory: (http, baseUrl) => (T) => new Service<T>(http, baseUrl), deps: [Http, new Inject('baseUrl')]
]

@Injectable()
export class Service<T>{

    ...

    constructor(private http: Http, @Inject('baseUrl') baseUrl: string ) {
        this.baseUrl = baseUrl;
    }

export class ProgramComponent implements OnInit {
    ...
    constructor(private route: ActivatedRoute, 
       @Inject(Service) private tennisService: Service<IProgram>, // fixed type parameter
       @Inject('ServiceIProgram') private tennisService: Service<IProgram>,

       @Inject('Service') serviceFactory:any // factory to instantiate yourself
    ) {
        // not sure if passing generic type parameters this way is supported by TypeScript
        this.tennisService = serviceFactory(IProgram);
    }

Angular 2 - 如何将参数传递给抽象服务

1 个答案: