Question

以下查询获得以下内容。

Service Date  Product1 Product2 
01/Jun/2015    1           3
02/Jun/2015    2           5

而不是我希望日期在列中，所以输出应该是这样的。

Products  01/Jun/2015  02/Jun/2015 
Product1    1           3
Product2    2           5

查询

DECLARE @cols AS nvarchar(max),
        @query AS nvarchar(max)
SELECT
  @cols = STUFF((SELECT
    ',' + QUOTENAME(Product_Name)
  FROM dbo.Store where CatID='2'

  GROUP BY Product_Name
  ORDER BY Product_Name
  FOR xml PATH (''), TYPE)
  .value('.', 'NVARCHAR(MAX)'), 1, 1, '')
SET @query = 'SELECT Replace(CONVERT(NVARCHAR, Service_Date, 106), '' '', ''/'') AS [Service Date],' + @cols + ' from ( select Service.Service_Date, Store.Product_Name, Servicelist.ProductQty FROM   dbo.Service INNER JOIN dbo.Servicelist ON dbo.Service.Service_ID = dbo.Servicelist.Service_ID INNER JOIN dbo.Store ON dbo.Servicelist.Pro_ID = dbo.Store.Pro_ID) x pivot ( SUM(ProductQty) for Product_Name in (' + @cols + ') ) p '
EXECUTE (@query);

Answer 1

您当前的查询是轮换产品名称并对日期进行分组。但您需要透视日期并将产品名称分组

试试这种方式

DECLARE @cols  AS NVARCHAR(max),
        @query AS NVARCHAR(max)

查找明确的日期列表而不是产品名称

SELECT @cols = Stuff((SELECT ','
                             + Quotename(CONVERT(char(11), Service_Date, 106))
                      FROM   dbo.Store
                      WHERE  CatID = '2'
                      GROUP  BY CONVERT(char(11), Service_Date, 106)
                      ORDER  BY CONVERT(date, Service_Date)
                      FOR xml PATH (''), TYPE) .value('.', 'NVARCHAR(MAX)'), 1, 1, '')

在透视for列表中，使用Service_date列代替Product_Name

SET @query = 'SELECT Product_Name,'
             + @cols
             + ' from ( select Service.Service_Date, Store.Product_Name, Servicelist.ProductQty FROM   dbo.Service INNER JOIN dbo.Servicelist ON dbo.Service.Service_ID = dbo.Servicelist.Service_ID INNER JOIN dbo.Store ON dbo.Servicelist.Pro_ID = dbo.Store.Pro_ID) x pivot ( SUM(ProductQty) for CONVERT(char(11), Service_Date, 106) in ('
             + @cols + ') ) p '

EXECUTE (@query);

Answer 2

这是使用普通ANSI SQL完成的。

首先，你需要垂直转动 - 在TRANSACT-SQL中说UNPIVOT - 你可以通过CROSS JOINING来做一个单列临时表，其中包含与你有值的＆＃34; unpivot＆＃34;一样多的连续整数。您可以将这些整数用作值的CASE WHEN表达式中的索引。

然后，使用SUM（CASE WHEN ...）表达式重新转动，并使用GROUP BY在第一列中垂直查看其值的列。

这里是：

WITH
-- input
input(Service_Date,Product1,Product2) AS (
          SELECT DATE '2015-06-01',1,3
UNION ALL SELECT DATE '2015-06-02',2,5
)          
,
-- start vertical pivot: two integers
two_ints(idx) AS (SELECT 1 UNION ALL SELECT 2)
,
-- vertical pivot: CROSS JOIN input with two integers
vert_pivot AS (
SELECT
  Service_Date
, idx
, 'Product'||CAST(idx AS CHAR(1)) AS product
, CASE idx WHEN 1 THEN Product1 WHEN 2 THEN Product2 END AS qty
FROM input CROSS JOIN two_ints
)
-- debug
-- SELECT * FROM vert_pivot;
-- Service_Date|idx|product |qty
-- 2015-06-01  |  1|Product1|  1
-- 2015-06-01  |  2|Product2|  3
-- 2015-06-02  |  1|Product1|  2
-- 2015-06-02  |  2|Product2|  5
,
-- re-pivot horizontally by date
horiz_pivot_dt AS (
SELECT
  product
, SUM(CASE Service_Date WHEN '2015-06-01' THEN qty END) AS "2015-06-01"
, SUM(CASE Service_Date WHEN '2015-06-02' THEN qty END) AS "2015-06-02"
FROM vert_pivot
GROUP BY
  product
)
SELECT * FROM horiz_pivot_dt
;
-- result:
-- product |2015-06-01|2015-06-02
-- Product1|         1|         2
-- Product2|         3|         5

顺便说一句：我注意到你只是转移了＃34;列名称＆＃34;和第一列的值 - 而不是措施。我上面的例子做了，我花了几分钟试图找出我的错误在哪里....

快乐的比赛...... 马可

Pivot sql将行转换为列

2 个答案: