在选择中显示最低值

Question

我试图获得一组中最低值的1个结果。所以我有一组数字（平均值）我只需要显示最低的一组：

Node(T value):
    nodeValue(value),
    leftSon(),
    rightSon(),
    isEmpty(false) {
}

我一直在尝试使用php min（）函数无效！

我的结果通常会像2,2.75,3,3.35等。所以我只需要显示最低的设置。所以像上面那样2。

Answer 1

您可以将所有值添加到数组中，并使用数组函数来确定获胜者

if ($danresult->num_rows > 0) {
    while($row = $danresult->fetch_assoc()) {
        $scores=array(
            $row["score_1"],
            $row["score_2"],
            $row["score_3"],
            $row["score_4"],
            $row["score_5"],
            $row["score_6"],
            $row["score_7"],
            $row["score_8"]
        );
        $sum= array_sum ($scores);
        $totalAverage = $sum / count($scores);
        $min=min($scores);

        $winner=array_search($min, $scores);
     }
}

Answer 2

试试这个，你需要关闭foreach ...然后从数组中获得最低值

if ($danresult->num_rows > 0) {
            while($row = $danresult->fetch_assoc()) {

                $score1 = $row["score_1"];
                $score2 = $row["score_2"];
                $score3 = $row["score_3"];
                $score4 = $row["score_4"];
                $score5 = $row["score_5"];
                $score6 = $row["score_6"];
                $score7 = $row["score_7"];
                $score8 = $row["score_8"];

                $sum = $score1 + $score2 + $score3 + $score4 + $score5 + $score6 + $score7 + $score8;
                $totalAverage = $sum / 8;

                $totalAverages[] = $totalAverage;
                }
                $index = min($totalAverages);
                echo $index . '<br>';
          }