在同一列上获取具有不同数据的行

Question

我们有像

这样的表格结构

Fieldid userid data
41       2      1
12       2      0
41       3      1
12       3      1

我们希望用户拥有（data = 1和filedid = 41）和（data = 0 and filedid = 12）

我们尝试了查询

select userid from table 
where (data=1 and filedid = 41) 
AND (data = 0 and filedid=12)

但它返回空结果。 任何人都可以帮助我们如何使用MySQL获取记录吗？

Answer 1

您可以在HAVING子句中使用条件聚合进行分组：

SELECT userid
FROM mytable
GROUP BY userid
HAVING COUNT(CASE WHEN data = 1 AND FieldId = 1 THEN 1 END) >= 1 AND
       COUNT(CASE WHEN data = 0 AND FieldId = 12 THEN 1 END) >= 1

Answer 2

与@Giorgos类似，多列比较简洁：

select userid
from t
group by userid
having  sum((data,fieldId) = (1, 41)) > 0
    and sum((data,fieldId) = (0, 12)) > 0

Answer 3

您需要使用union all，例如：

select * from table1 where Fieldid = 41 and data = 1 union all
select * from table1 where Fieldid = 12 and data = 0

附图显示输出

Answer 4

使用一组或另一组数据搜索结果时，您必须使用//Create a list containing all the elements from the callendar. IList<WebElement> listOfElements = new IList<WebElement>(); listOfElements = driver.FindElements(By.XPath("//div[@class='rc-row rc-widget-header']/table/thread/tr/th")); //Search for the one that matches the element that you are looking for. foreach(IWebElement element in listOfElements){ if(element.Text.equals("Sun 1/22"){ element.Click(); } } 关键字，而不是OR。

AND