我的class FloatingTabBarPercentDrivenInteraction: UIPercentDrivenInteractiveTransition {
var interactionInProgress = false
private var shouldCompleteTransition = false
private weak var tabBarViewController: FloatingTabBarViewController!
func wireToViewController(viewController: UIViewController!) {
self.tabBarViewController = viewController as! FloatingTabBarViewController
prepareGestureRecognizerInView(view: viewController.view)
}
private func prepareGestureRecognizerInView(view: UIView) {
let gestureRecognizer = UIPanGestureRecognizer(target: self, action: #selector(handleGesture(gestureRecognizer:)))
view.addGestureRecognizer(gestureRecognizer)
}
func handleGesture(gestureRecognizer: UIPanGestureRecognizer) {
let translation = gestureRecognizer.translation(in: gestureRecognizer.view)
var progress = (translation.x / 200)
progress = CGFloat(fminf(fmaxf(Float(progress), 0.0), 1.0))
switch gestureRecognizer.state {
case .began:
interactionInProgress = true
tabBarViewController.selectedIndex = 1
case .changed:
shouldCompleteTransition = progress > 0.3
update(progress)
case .cancelled:
interactionInProgress = false
cancel()
case.ended:
interactionInProgress = false
if !shouldCompleteTransition {
cancel()
} else {
finish()
}
default:
print("Unsupported")
}
}
}
if (ds.Tables.Count > 1)
{
if (ds.Tables[0].Rows.Count > 0)
{
dt = ds.Tables[0];
dr = dt.Rows[0];
TempData["AgentId"] = dr[0].ToString();
TempData["AgentCode"] = dr[1].ToString();
TempData["CenterName"] = dr[2].ToString();
TempData["LevelName"] = dr[3].ToString();
Session["AgentId"] = dr[0].ToString();
Session["LogInSession"] = SessionId;
return RedirectToAction("DashBoard", this.View(new AgentDetails { AgentId = Session["AgentId"].ToString() }));
//return this.View("DashBoard", new AgentDetails { AgentId = Session["AgentId"].ToString()});
}
查询按预期工作：
MySQL但是我的意图是将这些值放入表格中。
目前我想将结果放在新表JOIN：
SELECT subjectmie_subclasss.id AS subcl, subjectmie_classs.id AS cla,
subjectmie_subject.id AS subj,
CONCAT_WS(', ' ,subjectmie_subclasss.subclasss, subjectmie_classs.classs, subjectmie_subject.subject)
AS subjectcl
FROM subjectmie_subclasss
INNER JOIN subjectmie_subject
ON subjectmie_subject.id = subjectmie_subclasss.subject_id
LEFT JOIN subjectmie_classs
ON subjectmie_classs.id = subjectmie_subclasss.classs_id;
此subject_classs显然不正确，它在我执行查询之前显示INSERT INTO subject_classs
(subject_id, classs_id, subclasss_id, subject_classs)
SELECT subjectmie_subject.id AS subj, subjectmie_classs.id AS cla,
subjectmie_subclasss.id AS subcl,
CONCAT_WS(', ' ,subjectmie_subclasss.subclasss, subjectmie_classs.classs, subjectmie_subject.subject)
AS subjectcl
FROM subjectmie_subclasss
INNER JOIN subjectmie_subject
ON subjectmie_subject.id = subjectmie_subclasss.subject_id
LEFT JOIN subjectmie_classs
ON subjectmie_classs.id = subjectmie_subclasss.classs_id;
VALUES(subj, cla, subcl, subjectcl)
中的错误，因此查询逻辑错误。有人可以告诉我如何在我的QUERY查询中使用MySQL workbench。
答案 0 :(得分：1)
只需删除values子句即可：
INSERT INTO subject_classs
(subject_id, classs_id, subclasss_id, subject_classs)
SELECT subjectmie_subject.id AS subj, subjectmie_classs.id AS cla,
subjectmie_subclasss.id AS subcl,
CONCAT_WS(', ' ,subjectmie_subclasss.subclasss, subjectmie_classs.classs, subjectmie_subject.subject)
AS subjectcl
FROM subjectmie_subclasss
INNER JOIN subjectmie_subject
ON subjectmie_subject.id = subjectmie_subclasss.subject_id
LEFT JOIN subjectmie_classs
ON subjectmie_classs.id = subjectmie_subclasss.classs_id;