Question

需要拔出有寻呼机的员工。


<Employees>
  <Employee>
    <Name>Michael</Name>    
    <Phone Type="Home">423-555-0124</Phone>
    <Phone Type="Work">800-555-0545</Phone>
    <Phone Type="Mobile">424-555-0546</Phone>
    <Phone Type="Cell">424-555-0547</Phone>
    <Phone Type="Pager">424-555-0548</Phone>
  </Employee>
 <Employee>
    <Name>Jannet</Name>    
    <Phone Type="Home">423-555-0091</Phone>
    <Phone Type="Work">800-555-0545</Phone>
  </Employee>
</Employees>

我有LINQ来获取所有拥有寻呼机的Phone节点，我可以获得所有员工。我无法将我的脑袋包裹到电话节点，但仍然选择员工节点？


var data = XElement.Load(@"employee.XML" );
var whoHasPager = from teamMember in data.Elements("Employee")
                where (string)teamMember.Element("Phone").Attribute("Type") == "Pager"
                select teamMember;

Answer 1

这个怎么样：

var whoHasPager = from teamMember in data.Elements("Employee")
                where teamMember.Elements("Phone").Any(
                    p => p.Attribute("Type").Value == "Pager")
                select teamMember;

Answer 2

问题是.Element将返回第一个元素，而不是所有类型的电话。

Answer 3

您应该将其视为SQL语句

SELECT employee from Employees where Phone Type='Pager'

因此，from语句应该是Employees ... 注意：我在LINQ中并不是很擅长，但我认为这个想法是一样的......

Answer 4

您可以尝试使用XPath expression：

var data = XElement.Load(@"employee.XML" );
var whoHasPager =
    from teamMember in data.Elements("Employee")
    where teamMember.XPathSelectElement("Phone[@Type='Pager']") != null
    select teamMember;

Answer 5

var whoHasPager = doc.XPathSelectElements(
    "//Employee/Phone[@Type = 'Pager']/.."
);

Answer 6

试试这个：

var whoHasPager = from teamMember in data.Elements("Employee")
                  where teamMember.Elements("Phone").Any(x => x.Attribute("Type").Value == "Pager")
                  select teamMember;

LINQ to XML按重复的子节点属性选择节点

6 个答案: