我希望能够按类名对表中的行进行排序,以便所有具有类selected
的行首先出现,rejected
出现在最后。
为了澄清,我想改变这个
<table>
<tbody>
<tr><td><span class="selected">WAHEED</span></td></tr>
<tr><td><span class="selected">DON</span></td></tr>
<tr><td><span class="rejected">JACK</span></td></tr>
<tr><td><span class="selected">MARK</span></td></tr>
<tr><td><span class="rejected">GATEES</span></td></tr>
</tbody>
</table>
这样的事情:
<table>
<tbody>
<tr><td><span class="selected">WAHEED</span></td></tr>
<tr><td><span class="selected">MARK</span></td></tr>
<tr><td><span class="selected">DON</span></td></tr>
<tr><td><span class="rejected">JACK</span></td></tr>
<tr><td><span class="rejected">GATEES</span></td></tr>
</tbody>
</table>
请注意两个代码示例之间的顺序变化 关于如何实现这个目标的任何想法?
答案 0 :(得分:2)
这应该这样做:
var rows = document.querySelectorAll('table.sorted tr');
for (i = 0; i < rows.length; i++) {
if (rows[i].querySelector('span.rejected')) {
rows[i].closest('tbody').appendChild(rows[i]);
}
}
&#13;
<table class="sorted">
<tbody>
<tr><td> 1. </td><td><span class="selected">WAHEED</span></td></tr>
<tr><td> 2. </td><td><span class="selected">DON</span></td></tr>
<tr><td> 3. </td><td><span class="rejected">JACK</span></td></tr>
<tr><td> 4. </td><td><span class="selected">MARK</span></td></tr>
<tr><td> 5. </td><td><span class="rejected">GATEES</span></td></tr>
</tbody>
</table>
&#13;
它会在页面中<table>
的所有sorted
上运行,其中<tr>
类的位置rejected
包含最后一个MySQL
类的范围(所以其他所有保持在上面)。随意修改它以满足您的需求,它非常直接。
答案 1 :(得分:1)
你的意思是这样吗
var people, asc1 = 1,
asc2 = 1,
asc3 = 1;
window.onload = function () {
people = document.getElementById("people");
}
function sort_table(tbody, col, asc) {
var rows = tbody.rows,
rlen = rows.length,
arr = new Array(),
i, j, cells, clen;
// fill the array with values from the table
for (i = 0; i < rlen; i++) {
cells = rows[i].cells;
clen = cells.length;
arr[i] = new Array();
for (j = 0; j < clen; j++) {
arr[i][j] = cells[j].innerHTML;
}
}
// sort the array by the specified column number (col) and order (asc)
arr.sort(function (a, b) {
return (a[col] == b[col]) ? 0 : ((a[col] > b[col]) ? asc : -1 * asc);
});
// replace existing rows with new rows created from the sorted array
for (i = 0; i < rlen; i++) {
rows[i].innerHTML = "<td>" + arr[i].join("</td><td>") + "</td>";
}
}