Question

在下面的示例中，我尝试使用sun.tools.javac.Main动态编译我生成的类，然后实例化该类的对象并调用方法。到目前为止，我甚至无法通过加载生成的类。我在Eclipse中得到以下异常：

java.lang.ClassNotFoundException: TestHello_1289950330167
    at java.net.URLClassLoader$1.run(Unknown Source)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.net.URLClassLoader.findClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at java.lang.ClassLoader.loadClassInternal(Unknown Source)
    at java.lang.Class.forName0(Native Method)
    at java.lang.Class.forName(Unknown Source)
    at MyClassGenerator.runIt(MyClassGenerator.java:47)
    at MyClassGenerator.main(MyClassGenerator.java:13)
Note: sun.tools.javac.Main has been deprecated.
1 warning
Running TestHello_1289950330167:

以下是代码：

import java.io.ByteArrayOutputStream;
import java.io.File;
import java.io.FileWriter;
import java.net.URL;
import java.net.URLClassLoader;

public class MyClassGenerator {
    String generatedClassName = "TestHello_" + System.currentTimeMillis();
    String javaFileName = this.generatedClassName + ".java";

    public static void main(final String args[]) {
        final MyClassGenerator mtc = new MyClassGenerator();
        mtc.createIt();
        if (mtc.compileIt()) {
            System.out.println("Running " + mtc.generatedClassName + ":\n\n");
            mtc.runIt();
        }
        else {
            System.out.println(mtc.javaFileName + " is bad.");
        }
    }

    public void loadIt() {

        final ClassLoader classLoader = MyClassGenerator.class.getClassLoader();

        try {
            final Class aClass = classLoader.loadClass(this.generatedClassName);
            System.out.println("Loaded " + aClass.getName());
        }
        catch (final ClassNotFoundException e) {
            e.printStackTrace();
        }

    }

    public void createIt() {
        try {
            final FileWriter aWriter = new FileWriter(this.javaFileName, true);
            aWriter.write("public class " + this.generatedClassName + " { }");
            aWriter.flush();
            aWriter.close();
        }
        catch (final Exception e) {
            e.printStackTrace();
        }
    }

    public boolean compileIt() {
        final String[] source = { new String(this.javaFileName) };
        final ByteArrayOutputStream baos = new ByteArrayOutputStream();

        new sun.tools.javac.Main(baos, source[0]).compile(source);

        System.out.print(baos.toString());

        return (baos.toString().indexOf("error") == -1);
    }

    public void runIt() {
        try {
            final File file = new File(this.javaFileName);
            final URLClassLoader classLoader = URLClassLoader.newInstance(new URL[] { file.toURI().toURL() });
            final Class<?> cls = Class.forName(this.generatedClassName, true, classLoader);
        }
        catch (final Exception e) {
            e.printStackTrace();
        }
    }
}

Answer 1

因为它不在类路径中。将其写入类路径（或将其根路径添加到类路径）或使用URLClassLoader。

File root = new File(".");
URLClassLoader classLoader = URLClassLoader.newInstance(new URL[] { root.toURI().toURL() });
Class<?> cls = Class.forName(generatedClassName, true, classLoader);

使用java.io中的相对路径是一个坏主意。您依赖于当前工作目录，该目录在代码中无法控制。

Answer 2

您正在创建一个指向具体文件的新URLClassLoader。表达为命令行参数，你这样做：

java -cp file:///foo/bar/TestHello_1289950330167.java

然后你的代码会调用它：

Class.forName("TestHello_1289950330167",true,cl);

类路径是JAR文件或文件夹，而不是.java文件！

您应该做的是创建一个UR ".".toURI().toURL()作为类路径的URLClassLoader，而不是javaFileName。

使用Class.forName（...）时为什么会出现ClassNotFoundException？

2 个答案: