Question

如何让microsoft unity“构造”给定接口类型的类列表。

非常简单的例子：

  List<IShippingCalculation> list = new List<IShippingCalculation>();
  list.Add(new NewYorkShippingCalculation());
  list.Add(new FloridaShippingCalculation());
  list.Add(new AlaskShippingCalculation());

  //Not What I want
  public void calcship(List<IShippingCalculation> list)
  {
    var info = new ShippingInfo(list);
    info.CalculateShippingAmount(State.Alaska)
  }

  //Somehow in unity, must i do this for all the concrete classes? 
  //how does it know to give a list.
  Container.RegisterType<IShippingInfo,new AlaskaShippingCalculation()>();??

  //What I want
  public void calcship(IShippingInfo info)
  {
    info.CalculateShippingAmount(State.Alaska)
  }

三江源！

Answer 1

如果您使用的是Unity 2，则可以使用ResolveAll<T>

Container.RegisterType<IShippingInfo,FloridaShippingCalculation>("Florida");
Container.RegisterType<IShippingInfo,NewYorkShippingCalculation>("NewYork");
Container.RegisterType<IShippingInfo,AlaskaShippingCalculation>("Alaska");

IEnumerable<IShippingInfo> infos = Container.ResolveAll<IShippingInfo>();

您必须为每个注册命名，因为ResolveAll只会返回命名注册。

Answer 2

您不需要将容器作为参数，使用如上所述的名称注册具体类型，然后在构造函数中添加数组作为参数，IList或通用枚举不起作用。

public MyConstructor(IMyType[] myTypes)

Unity解析多个类

2 个答案: