我有一张表，其中包含与客户进行团队咨询的开始和结束日期。
我需要根据另一栏中指定的天数合并某些咨询（有时协商可能会重叠，有时它们是连续的，有时它们不是），团队和类型。
一些示例数据如下：
DECLARE @TempTable TABLE([CUSTOMER_ID] INT
,[TEAM] VARCHAR(1)
,[TYPE] VARCHAR(1)
,[START_DATE] DATETIME
,[END_DATE] DATETIME
,[GROUP_DAYS_CRITERIA] INT)
INSERT INTO @TempTable VALUES (1,'A','A','2013-08-07','2013-12-31',28)
,(2,'B','A','2015-05-15','2015-05-28',28)
,(2,'B','A','2015-05-15','2016-05-12',28)
,(2,'B','A','2015-05-28','2015-05-28',28)
,(3,'C','A','2013-05-27','2014-07-23',28)
,(3,'C','A','2015-01-12','2015-05-28',28)
,(3,'B','A','2015-01-12','2015-05-28',28)
,(3,'C','A','2015-05-28','2015-05-28',28)
,(3,'C','A','2015-05-28','2015-12-17',28)
,(4,'A','B','2013-07-09','2014-04-21',7)
,(4,'A','B','2014-04-29','2014-08-01',7)
看起来像这样：
+-------------+------+------+------------+------------+---------------------+
| CUSTOMER_ID | TEAM | TYPE | START_DATE | END_DATE | GROUP_DAYS_CRITERIA |
+-------------+------+------+------------+------------+---------------------+
| 1 | A | A | 07/08/2013 | 31/12/2013 | 28 |
| 2 | B | A | 15/05/2015 | 28/05/2015 | 28 |
| 2 | B | A | 15/05/2015 | 12/05/2016 | 28 |
| 2 | B | A | 28/05/2015 | 28/05/2015 | 28 |
| 3 | C | A | 27/05/2013 | 23/07/2014 | 28 |
| 3 | C | A | 12/01/2015 | 28/05/2015 | 28 |
| 3 | B | A | 12/01/2015 | 28/05/2015 | 28 |
| 3 | C | A | 28/05/2015 | 28/05/2015 | 28 |
| 3 | C | A | 28/05/2015 | 17/12/2015 | 28 |
| 4 | A | B | 09/07/2013 | 21/04/2014 | 7 |
| 4 | A | B | 29/04/2014 | 01/08/2014 | 7 |
+-------------+------+------+------------+------------+---------------------+
我想要的输出如下：
+-------------+------+------+------------+------------+---------------------+
| CUSTOMER_ID | TEAM | TYPE | START_DATE | END_DATE | GROUP_DAYS_CRITERIA |
+-------------+------+------+------------+------------+---------------------+
| 1 | A | A | 07/08/2013 | 31/12/2013 | 28 |
| 2 | B | A | 15/05/2015 | 12/05/2016 | 28 |
| 3 | C | A | 27/05/2013 | 23/07/2014 | 28 |
| 3 | C | A | 12/01/2015 | 17/12/2015 | 28 |
| 3 | B | A | 12/01/2015 | 28/05/2015 | 28 |
| 4 | A | B | 09/07/2013 | 21/04/2014 | 7 |
| 4 | A | B | 29/04/2014 | 01/08/2014 | 7 |
+-------------+------+------+------------+------------+---------------------+
我正在努力做到这一点，更不用说任何效率了！任何想法/代码都将受到极大的欢迎。
服务器版本是MS SQL Server 2014
谢谢，
丹
答案 0 :(得分：1)
如果我正确理解您的问题，我们希望仅在上一次咨询结束日期后的group_days_criteria天数内未发生第二次，第三次等咨询时返回行。
我们可以获得之前的咨询结束日期并消除行（因为我们不关心咨询的数量），同一团队在同一个客户和我们日期范围内的同一咨询类型进行协商。
DECLARE @TempTable TABLE([CUSTOMER_ID] INT
,[TEAM] VARCHAR(1)
,[TYPE] VARCHAR(1)
,[START_DATE] DATETIME
,[END_DATE] DATETIME
,[GROUP_DAYS_CRITERIA] INT)
INSERT INTO @TempTable VALUES (1,'A','A','2013-08-07','2013-12-31',28)
,(2,'B','A','2015-05-15','2015-05-28',28)
,(2,'B','A','2015-05-15','2016-05-12',28)
,(2,'B','A','2015-05-28','2015-05-28',28)
,(3,'C','A','2013-05-27','2014-07-23',28)
,(3,'C','A','2015-01-12','2015-05-28',28)
,(3,'B','A','2015-01-12','2015-05-28',28)
,(3,'C','A','2015-05-28','2015-05-28',28)
,(3,'C','A','2015-05-28','2015-12-17',28)
,(4,'A','B','2013-07-09','2014-04-21',7)
,(4,'A','B','2014-04-29','2014-08-01',7)
;with prep as (
select Customer_ID,
Team,
[Type],
[Start_Date],
[End_Date],
Group_Days_Criteria,
ROW_NUMBER() over (partition by customer_id, team, [type] order by [start_date] asc, [end_date] desc) as rn, -- earliest start date with latest end date
lag([End_Date] + Group_Days_Criteria, 1, 0) over (partition by customer_id, team, [type] order by [start_date] asc, [end_date] desc) as PreviousEndDate -- previous end date +
from @TempTable
)
select p.Customer_Id,
p.[Team],
p.[Type],
p.[Start_Date],
p.[End_Date],
p.Group_Days_Criteria
from prep p
where p.rn = 1
or (p.rn != 1 and p.[Start_date] > p.PreviousEndDate)
order by p.Customer_Id, p.[Team], p.[Start_Date], p.[Type]
这返回了所需的结果集。