Question

我们使用java创建了一个与sqlite数据库连接的软件。一切正常。但是当我们按下按钮打开数据库时，我们收到一条消息，表明数据库已被锁定。 [SQLITE_BUSY] The database file is locked (database is locked)

所以我们根本不能使用它..错误的原因是什么？我们怎样才能解决它？

此代码适用于我们遇到问题的按钮：

String id_patient = id.getText();

int idd, idd1 = 0;
idd = Integer.valueOf(first011.a55); //first011.a55 = id_patient

Connection connection22;
Statement statement22, stat, statement44, statement2;

connection22 = null;
try {
 connection22 = DriverManager.getConnection("jdbc:sqlite:D:\\workspace\\FAMRSOFTWARE\\dataessai.sqlite");
 statement2 = connection22.createStatement();
 statement2.setQueryTimeout(30);
 statement22 = connection22.createStatement();
 statement22.setQueryTimeout(30);
 stat = connection22.createStatement();
 stat.setQueryTimeout(30);

 statement44 = connection22.createStatement();
 statement44.setQueryTimeout(30);


 //This is to take and use id_demand from an other table in database

 ResultSet Resultat = statement22.executeQuery("SELECT * FROM demandes WHERE ID_patient =" + first011.a55);
 while (Resultat.next()) {
  String iddemande = Resultat.getString("ID_demande");
  idd1 = Integer.valueOf(iddemande);
 }


 int i = 0;
 int string;
 String idanalyse;
 while (i < tablee.getRowCount()) {
  if (!(tablee.getValueAt(i, 0) == null)) {

   statement22.executeUpdate("INSERT INTO datails (ID_demande, ID_analyse ) VALUES ('" + idd1 + "', '" + Integer.valueOf((String) tablee.getValueAt(i, 0)) + "')");
   i++;

  } else {
   break;
  }
 }


 i = 0;
 while (i < tablee.getRowCount()) {
  if (!(tablee.getValueAt(i, 0) == null)) {

   ResultSet Resultat2 = statement44.executeQuery("SELECT * FROM parametres WHERE ID_analyse =" + tablee.getValueAt(i, 0));
   while (Resultat2.next()) {
    stat.executeUpdate("INSERT INTO fichetechnique (ID_patient, ID_parametre, ID_analyse ) VALUES ('" + id.getText() + "', '" + Resultat2.getString("ID_parametre") + "', '" + tablee.getValueAt(i, 0) + "')");

   }

   i++;
  } else break;
 }
 statement2.executeUpdate("UPDATE demandes SET total = '" + apayer.getText() + "',versement = '" + v.getText() + "' WHERE ID_patient = " + first011.a55);
 //statement2.executeUpdate("UPDATE demandes SET  versement = '"+v.getText()+"' WHERE ID_patient = "+first011.a55);

 JOptionPane.showMessageDialog(null, "Les Analyses de ce patient est enregistrer avec succès !! ");

} catch (SQLException e1) {

 System.err.println(e1.getMessage());
}


setVisible(false);

SQLite数据库文件被锁定（数据库被锁定）

0 个答案: