如何计算数组中哪些键存在值？

Question

 $count = array(1 => 'one', 2 => 'two', 3 => 'three', 4=>'');

数组有四个值，一个键没有值。

我想显示哪个键有值的数组的数量。

Answer 1

试试这个，

$array = array(1 => 'one', 2 => 'two', 3 => 'three', 4=>'');
$count = count(array_filter($array));
echo $count;

Answer 2

使用array_filter并过滤掉所有值为空的键

print_r(array_filter($count, create_function('$value', 'return $value !== "";')));

Answer 3

//Use functions array_filter() and count()    
$fullarray = array(1 => 'one', 2 => 'two', 3 => 'three', 4=>'');
$filteredArray = array_filter($fullarray);//filters the values of an array using a callback function
$count=count($filteredArray);//returns the number of elements in an array.
print_r($count);//display count