是否有一个单行程序在PowerShell中创建LocalDB数据库(而不是实例)?

时间:2017-02-09 11:03:19

标签: powershell localdb

我想以MDF和LDF文件保留在脚本执行文件夹中的方式创建LocalDB数据库。

  • 我知道我们可以轻松地在PowerShell中使用$运算符进行命令替换,因此,如果我声明$pwd之类的内容,它将替换为pwd的输出}命令。

  • here开始,我知道Invoke-SqlCmd不是使用LocalDB实例做事的简单方法。

  • 我想通过PowerShell执行以下命令。我怎么能做到这一点?

    sqlcmd -S "(localdb)\MSSQLLocalDB" -Q "
    CREATE DATABASE [Test] ON PRIMARY ( 
            NAME = N'Test', 
            FILENAME = N'<$pwd output here>\Test.mdf'
    ) 
    LOG ON ( 
            NAME = N'Test_log', 
            FILENAME = N'<$pwd output here>\Test_log.ldf'
    )"
    

1 个答案:

答案 0 :(得分:1)

这可能比您要求的要多得多,但它会解决您的问题。

这将询问您是否要从模板还原,否则它将创建一个空数据库。

$backupFilePath=''
$TempDB=''
$TempDBlog=''
$DBName=''
$Logfilepath=''
$Datafilepath=''

$confirmation = Read-Host "Do you want to use a DB template? [y/n]"

If($confirmation.ToUpper().StartsWith("Y") )
{
$dbCommand = "use [master];RESTORE DATABASE [$DBName] " + "FROM DISK = N'$backupFilePath'" + "WITH FILE = 1, NOUNLOAD, STATS = 10, " + "move '$TempDB' to '$Datafilepath" + "\" + "$DBName" + ".mdf', " + "move '$TempDBlog' to '$Logfilepath" + "\" + "$DBName" + ".ldf';" + "alter database [$DBName] modify file (name=N'$TempDB ', newname=N'$DBName" + "_data1');" + "alter database [$DBName] modify file (name=N'$TempDBlog', newname=N'$DBName" + "_log1');" + "alter database [$DBName] set read_committed_snapshot on with rollback immediate;" + "alter database [$DBName] set COMPATIBILITY_LEVEL = 100;"
}

else {
$dbCommand = "use [master];CREATE DATABASE [$DBName] ON " + "( NAME='$DBName" + "_data1', FILENAME='$Datafilepath" + "\" + "$DBName" + "_data1.mdf', SIZE=1GB, MAXSIZE=UNLIMITED, FILEGROWTH=200MB)" + "LOG ON ( NAME='$DBName" + "_log1', FILENAME='$Logfilepath" + "\" + "$DBName" + "_log1.ldf', SIZE=1GB, MAXSIZE=UNLIMITED, FILEGROWTH=200MB); " + "alter database [$DBName] set read_committed_snapshot on with rollback immediate;" + "alter database [$DBName] set COMPATIBILITY_LEVEL = 100; " + "set AUTO_CLOSE OFF;"
}

有人必须将其编辑为漂亮的代码中断,因为它不允许我这样做。

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