Question

我是python的新手，我正在卡住打印将要打印的功能：

＆＃34;墙上挂着99瓶啤酒99瓶啤酒拿下一个并将它传递到墙上，98瓶啤酒 98瓶啤酒在墙上98瓶啤酒拿下一个并将它传递到墙上，97瓶啤酒墙上挂着97瓶啤酒，97瓶啤酒拿下一个并将它传递给墙壁上的96瓶啤酒＆＃34;

这是我的代码：

def sing(number):
    number = 99
    print(number, "bottles of beer on the wall", number, "bottles of beer")
    print("Take one down and pass it around, ", end='')
    number -= 1
    print(number, "bottles of beer on the wall")
    return number

print(sing(sing(sing(number))))

有人可以帮我解决我出错的地方吗？非常感谢它。

由于

Answer 1

为什么不使用循环？您可以使用range从number向99步骤1。

def sing(number):
    print(number, "bottles of beer on the wall", number, "bottles of beer")
    print("Take one down and pass it around, ", end='')
    print(number-1, "bottles of beer on the wall")

for number in range(99, 0, -1):
    sing(number)

否则你可以在函数本身中添加一个循环

def sing(number):
    while number > 1:
        print(number, "bottles of beer on the wall", number, "bottles of beer")
        print("Take one down and pass it around, ", end='')
        number -= 1
        print(number, "bottles of beer on the wall")

sing(99)

Answer 2

您编写的代码问题在于，每次调用此函数时，您都需要重新定义number，而不是使用您传入的值。您可以通过删除函数的第一行来修复它，并且可以删除最终的print

def sing(number):
    print(number, "bottles of beer on the wall", number, "bottles of beer")
    print("Take one down and pass it around, ", end='')
    number -= 1
    print(number, "bottles of beer on the wall")
    return number

sing(sing(sing(99)))

多次打印功能

2 个答案: