Question

基本上我从php获取json格式的数据。我无法控制我得到的数据。示例输出为：

var Data={"2":[{"name":"Mr Samuel","votes":"11"}],[{"name":"Mrs Clair Cher","votes":"2"}],"3":[{"name":"Mr Madiex","votes":"13"}]};

数据是这样的：萨穆埃尔先生和克莱尔夫人在一个身份为2的部门工作，而麦迪克斯先生在部门3工作。投票是他们为表现而获得的选票。现在我需要遍历数据，获取名称和投票。

 $.each(Data, function(departmentid, staffmembers){
 //departmentid is well captured: 2 and 3. But I am having a hard time going thru each departments staff members:

  $.each(Data[departmentid], function(index,value){
   //here, i expected that Data[departmentid][index].name would give me name but it is undefined.
   });


});

我到底错过了什么？

Answer 1

在对原始问题中的代码进行更正后，它似乎有效（假设您已包含jQuery）：

var Data = {
    "2": [
        {"name":"Mr Samuel","votes":"11"},
        {"name":"Mrs Clair Cher","votes":"2"}
    ],
    "3": [
        {"name":"Mr Madiex","votes":"13"}
    ]
};

$.each(Data, function(departmentid, staffmembers){
    $.each(Data[departmentid], function(index,value){
        console.log(Data[departmentid][index].name );
    });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

当然，您也可以使用staffmembers和value参数：

var Data = {
    "2": [
        {"name":"Mr Samuel","votes":"11"},
        {"name":"Mrs Clair Cher","votes":"2"}
    ],
    "3": [
        {"name":"Mr Madiex","votes":"13"}
    ]
};

$.each(Data, function(departmentid, staffmembers){
    $.each(staffmembers, function(index,value){
        console.log(value.name );
    });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

使用数组子元素循环遍历此json数据

1 个答案: