Question

我有两个视图控制器。我创建了一个自定义segue，从第一个viewcontroller到第二个，反之亦然，将两个segue链接到下面的类:(我从互联网教程下载了这个类）

#import "SlideLeftCustomSegue.h"

@implementation SlideLeftCustomSegue

- (void)perform{
    UIViewController *srcViewController = (UIViewController *) self.sourceViewController;
    UIViewController *destViewController = (UIViewController *) self.destinationViewController;

    CATransition *transition = [CATransition animation];
    transition.duration = 0.3;
    transition.timingFunction = [CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut];
    transition.type = kCATransitionPush;
    transition.subtype = kCATransitionFromRight;
    [srcViewController.view.window.layer addAnimation:transition forKey:nil];

    [srcViewController presentViewController:destViewController animated:NO completion:nil];
}

@end

（我刚刚改变了从＃34;右＆＃34; lo＆＃34;左＆＃34;取决于我是哪个视图控制器）我通过轻扫手势调用segue。

它按预期工作，但有时，随机，当我轻扫以调用segue时，它会崩溃。这是出现的错误。

pru(745,0x1ae6d5c40) malloc: *** error for object 0x170014930:      Invalid pointer dequeued from free list
*** set a breakpoint in malloc_error_break to debug
(lldb)

我该如何解决这个问题？

Answer 1

像这样创建UIviewController obj

SomeViewController * someViewController = [self.storyboard instantiateViewControllerWithIdentifier：@“SomeViewController”];

滑动手势到下一个视图控制器崩溃

1 个答案: