针对多米诺骨牌的

Question

鉴于多米诺骨牌的安排，确定它是否是一种法律安排，并相应地返回真或假。例如，这是一项非法安排[2 3] [4 2] [2 2] [3 5]，这是多米诺的法律安排。 [2 3] [3 5] [5 4] [4 5]。

这是我现在的编码，但我希望它在合法时非法和合法时输出非法。有没有办法在编码和出局中安排哪些是非法的，哪个是合法的？

public class Domino {
   private int leftValue;
   private int rightValue;

    public Domino(int leftValue, int rightValue) {
       this.leftValue = leftValue;
       this.rightValue = rightValue;
   }

   public int getLeftValue() {
       return leftValue;
   }

   public int getRightValue() {
       return rightValue;
   }

    public static void main(String[] args) {
       // This creates the Array
       Domino[] dominos = new Domino[] {
           new Domino(2, 3),
           new Domino(3, 2),
           new Domino(2, 5),
           new Domino(2, 5) 
       };
       // This part Loops and matchs left and right values
       Domino previous = null;

       for (Domino current : dominos) {
           if (previous != null) {
               if (current.getLeftValue() != previous.getRightValue()) {
                   try {
                       throw new Exception("Illegal");
                   } catch (Exception e) {
                       e.printStackTrace();
                   } 
               }
           }
           previous = current;
       }
    }
}

Answer 1

您可以尝试使用以下代码替换for循环：

    for (Domino current : dominos) {
        if (previous != null) {
            if (current.getLeftValue() != previous.getRightValue()) {
                System.out.println("[" + previous.getLeftValue() + " " + previous.getRightValue()
                        + "][" + current.getLeftValue() + " " + current.getRightValue() + "] is illegal");
            } else {
                System.out.println("[" + previous.getLeftValue() + " " + previous.getRightValue()
                        + "][" + current.getLeftValue() + " " + current.getRightValue() + "] is legal");
            }
        }
        previous = current;
    }