Question

无法在python中突破while循环：我尝试将代码合并在一起，没有main和getheight函数，它仍然给我一个无限循环。

def main():
    x = 0
    while x not in range (1,23):
        getheight()
        if x in range (1,23):
            break
    for i in range (x):
        for j in range (x - j):
            print (" ", end="")
        for j in range (x):
            print ("#", end="")
        print ("  ", end="")
        for j in range (x):
            print ("#", end="")
        "\n"

def getheight():
    x = input("Give me a positive integer no more than 23 \n")
    return x

if __name__ == "__main__":
    main()

Answer 1

main()中的{p> x是getheight()中x变量独立的局部变量。您将从后者返回新值，但会返回返回的值。在函数调用结果中设置main中的

while x not in range (1,23):
    x = getheight()
    if x in range (1,23):
        break

：

getheight()

您还需要修复def getheight(): x = input("Give me a positive integer no more than 23 \n") return int(x)函数以返回整数，而不是字符串：

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Incoming email to pete@mydomain.com -> htaccess -> redirecting to myemail@gmail.com

Answer 2

返回并不意味着它会自动更新main中的任何变量名称与返回变量匹配。如果不存储此返回值，则返回值将消失。因此你必须这样做

x=getheight()

更新变量x

在python中无法突破while循环

2 个答案: