Question

我是sql的新手，我使用MS SQL Server，我有这个选择并加入

SELECT t1.number
    ,t2.site1 
    ,t2.Events_W
    ,t3.site1
    ,t3.Events_W_D
    ,t4.site1
    ,t4.Events_NW
    ,t5.site1
    ,t5.Events_NW_D
    FROM [TEST].[ak].[test3] AS t1
LEFT JOIN [TEST].[ak].[test2] AS T2
    ON t1.number=t2.number AND t1.Events_W = t2.Events_W 
LEFT JOIN [TEST].[ak].[test2] AS t3
    ON t1.number=t3.number  AND t1.Events_W_D=t3.Events_W_D 
LEFT JOIN [TEST].[ak].[test2] as t4
    ON t1.number=t4.number AND t1.Events_NW = t4.Events_NW 
LEFT JOIN [TEST].[ak].[test2] t5
    ON t1.number=t5.number AND t1.Events_NW_D=t5.Events_NW_D

结果如下：

Number  Site    |event_w    |site   |event_w_d  |site   |Event_nt   |site   |event_nw_d
anum    |2014   |116    |2014   |99     |2358   |163    |2087   |129
bnum    |1570   |17     |1570   |76     |1196   |99     |1196   |577
bnum    |1570   |17     |1905   |111    |1508   |26     |1508   |427
bnum    |1196   |3      |1475   |2      |1508   |1      |8263   |5
cnum    |2087   |15     |NULL   |NULL   |2087   |92     |NULL   |NULL
dnum    |1071   |14     |1905   |106    |1071   |21     |1426   |206
gnum    |2087   |36     |2087   |97     |2087   |92     |2087   |93
rnum    |123    |23     |123    |23     |NULL   |NULL   |NULL   |NULL

正确的结果必须是：

Number  |Site   |event_w    |site   |event_w_d  |site   |Event_nt   |site   |event_nw_d
anum    |2014   |116    |2014   |99     |2358   |163    |2087   |129
bnum    |1196   |3      |1475   |2      |1508   |1      |8263   |5
cnum    |2087   |15     |NULL   |NULL   |2087   |92     |NULL   |NULL
dnum    |1071   |14     |1905   |106    |1071   |21     |1426   |206
gnum    |2087   |36    |2087    |97     |2087   |92    |2087    |93

我需要通过数字区分，但不使用'区别'。

请帮忙！

Answer 1

Declare @Tep Table
(
name varchar(100), City Varchar(500), Contct1 bigInt)

INSERT INTO @Tep
select 'R', 'Delhi', 7827492235
Union All
select 'S', 'Noida', 8827492235

Union All
select 'P', 'Noida', 7827492235

Union All
select 't', 'r', 9827492235

--Get Unique Record Without Distinct
SELECT * FROM (
SELECT ROW_NUMBER() OVER(PARTITION BY Contct1 ORDER BY Contct1) As RowID, 
name, 
City , Contct1
FROM @Tep
)T  WHERE RowID=1

Answer 2

另请尝试下面的approch获得无与伦比的独特记录 SELECT * FROM（ SELECT ROW_NUMBER（）OVER（Contect1 ORDER BY Contct1的分区）作为RowID，名称，城市，Contct1 来自@Tep ）T WHERE Contct1 NOT In（

SELECT Contct1 FROM（ SELECT ROW_NUMBER（）OVER（Contect1 ORDER BY Contct1的分区）作为RowID，名称，城市，Contct1 来自@Tep ）T其中RowID = 2 ）

也尝试这种方式

如何在不使用Distinct的情况下区分行

2 个答案: