我正试图通过shell脚本触发Oozie作业。但是在执行shell脚本时出现以下错误:
“找不到命令”错误:ooziejob = $(oozie job -oozie http://oozieserver:port/oozie -config /root/SqoopWrapper1/sqoop_job.properties -run);
我的shell脚本由oozie命令组成;
input=/root/SqoopWrapper1/InputFile.txt
echo "internal field sep"
IFS='|'
while read SourceDB db_name Mysql_table hdfsdir libpath
do
echo "do...while"
if [ SourceDB = Mysql ]
then
driver = com.mysql.jdbc.Driver
jdbcUri = jdbc:mysql://host:3306
Mysql_table = WrapperTbl
UserName = ****
Password = ****
fi
echo "Oozie command exe"
ooziejob =$(oozie job -oozie http://oozieserver:port/oozie -config /root/SqoopWrapper1/sqoop_job.properties -run);
echo $ooziejob;
done < $input
exit 0
答案 0 :(得分:0)
你在等号之前有一个空格。
顺便说一句,如果你发布这类问题,你应该总是说出你正在使用的shell和操作系统。